All categories

3 years ago

The electron domain and molecular geometry of NF₃ are ________.

Chemistry

1 answer:

Anna35 [415]3 years ago

8 0

Answer:

The electron domain and molecular geometry of NF₃ are option b

Explanation:

First of all, think the total valence electrons of each element.

N : 5

F: 7, but we have 3, so 7.3 = 21

Total: 26 e⁻

Now let's draw a scheme

F ---- N ---- F

We have to put 26 e⁻ around the elements, so 6 e⁻ are been used for the bonds N-F, so now, there are 20 e⁻ to add. As the F, have used 1 e⁻ to form the bond, there are 6 more, around. Each fluorine which has 7 e⁻, shares 1e⁻ with the N, to complete the octet rule.

So, there are still 2e⁻ to add. They will be above the N and they are free. That's why the molecular geometric is trigonal, and the electronic geeometry is tetrahedral because the non-binding electron pair of N

You might be interested in

4) What volume will the gas in the balloon at right occupy at 250k? balloon: 4.3L 350K

swat32

Answer:

2.87 liter.

Explanation:

Given:

Initially volume of balloon = 4.3 liter

Initially temperature of balloon = 350 K

Question asked:

What volume will the gas in the balloon occupy at 250 K ?

Solution:

By using:

$Pv =nRT$

Assuming pressure as constant,

V∝ T

Now, let K is the constant.

V = KT

Let initial volume of balloon , $V_{1}$ = 4.3 liter

1000 liter = 1 meter cube

1 liter = $\frac{1}{1000} m^{3} = 10^{-3} m^{3$

4.3 liter = $4.3\times10^{-3}=4.3\times10^{-3} m^{3}$

And initial temperature of balloon, $T_{1}$ = 350 K

Let the final volume of balloon is $V_{2}$

And as given, final temperature of balloon, $T_{2}$ is 250 K

Now, $V_{1} = KT_{1}$

$4.3\times10^{-3}=K\times350\ (equation\ 1 )$

$V_{2} = KT_{2}$

$=K\times250\ (equation 2)$

Dividing equation 1 and 2,

$\frac{4.3\times10^{-3}}{V_{2} } =\frac{K\times350}{K\times250}$

K cancelled by K.

By cross multiplication:

$350V_{2} =4.3\times10^{-3} \times250\\V_{2} =\frac{ 4.3\times10^{-3} \times250\\}{350} \\ = \frac{1075\times10^{-3}}{350} \\ =2.87\times10^{-3}m^{3}$

Now, convert it into liter with the help of calculation done above,

$2.87\times10^{-3} \times1000\\2.87\times10^{-3} \times10^{3} \\2.87\ liter$

Therefore, volume of the gas in the balloon at 250 K will be 2.87 liter.

4 0

3 years ago

A balloon filled with helium occupies 20.0 l at 1.50 atm and 25.0◦c. How many moles of helium will there be in the balloon at st

satela [25.4K]

Answer:

There will be 1.23 moles of helium in the balloon at STP

Explanation:

1) Initial conditions of the helium gas:

V = 20.0 liter
p = 1.50 atm
T = 25.0 °C = 25.0 + 273.15 K = 298.15 K

2) Ideal gas equation:

pV = n RT
p, V, and T are given above
R is the Universal constant = 0.0821 atm-liter / ( K - mol)
n is the unknown number of moles

3) Solve for n:

n = pV / (RT) =

n = 1.50 atm × 20.0 liter / (0.0821 atm-liter /k -mol ×298.15K)

n = 1.23 mol

4) At STP:

STP stands for standard pressure and temperature.

The amount (number of moles) of the gas will not change because the change of pressure and temperature, so the number of moles reamain the same: 1.23 mol.

8 0

3 years ago

4. Fill in the blanks. Complete each sentence using a term from the word bank. (4)

skelet666 [1.2K]

Answer:

A.compound genuinely bozo L XL so

4 0

2 years ago

Which of the following planets has ammonia clouds in its atmosphere?

AlekseyPX

Answer:

Jupiter and Saturn has ammonia clouds in its atmosphere since the molecules of ammonia gas that are present in their atmospheres condense to form clouds. However, these ammonia clouds are more visible in Jupiter than in Saturn because of their lower altitude in Saturn.

6 0

3 years ago

How many unpaired electrons are there in Cu1+ ion

goldfiish [28.3K]

If electrons are negative, losing an electron makes the ion positive.
Therefore Cu1+ contains 1 unpaired electron.

8 0

3 years ago