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levacccp [35]
3 years ago
10

The electron domain and molecular geometry of NF₃ are ________.

Chemistry
1 answer:
Anna35 [415]3 years ago
8 0

Answer:

The electron domain and molecular geometry of NF₃ are option b

Explanation:

First of all, think the total valence electrons of each element.

N : 5

F: 7, but we have 3, so 7.3 = 21

Total: 26 e⁻

Now let's draw a scheme

             F   ----  N  ----  F

                          |

                         F

We have to put 26 e⁻ around the elements, so 6 e⁻ are been used for the bonds N-F, so now, there are 20 e⁻  to add. As the F, have used 1 e⁻ to form the bond, there are 6 more, around. Each fluorine which has 7 e⁻,  shares 1e⁻ with the N, to complete the octet rule.

So, there are still 2e⁻ to add. They will be above the N and they are free. That's why the molecular geometric is trigonal, and the electronic geeometry is tetrahedral because the non-binding electron pair of N

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Answer:

<em>Answer Below</em>

Explanation:

Percent composition by element

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Aluminium <u>Al</u>          34.590%

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Answer:

D

Explanation:

A covalent bond is said to be formed when two electrons are shared between two bonding atoms as in the formation of the water molecule.

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3 years ago
How many moles of nacl are required to make 500. 0 ml of a 0. 1 m solution of nacl?.
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Answer:

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Explanation:

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starting with the idea of isostasy and ending with plate tectonics, explain how scientists understanding of the earth's crust ha
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3 years ago
A 25.0-mL sample of 0.150 M hydrocyanic acid is titrated with a 0.150 M NaOH solution. The Ka of hydrocyanic acid is 4.9 × 10-10
lara [203]

Answer:

The pOH = 1.83

Explanation:

Step 1: Data given

volume of the sample = 25.0 mL

Molarity of hydrocyanic acid = 0.150 M

Molarity of NaOH = 0.150 M

Ka of hydrocyanic acid = 4.9 * 10^-10

Step 2: The balanced equation

HCN + NaOH → NaCN + H2O

Step 3: Calculate the number of moles hydrocyanic acid (HCN)

Moles HCN = molarity * volume

Moles HCN = 0.150 M * 0.0250 L

Moles HCN = 0.00375 moles

Step 3: Calculate moles NaOH

Moles NaOH = 0.150 M * 0.0305 L

Moles NaOH = 0.004575 moles

Step 4: Calculate the limiting reactant

0.00375 moles HCN will react with 0.004575 moles NaOH

HCN is the limiting reactant. It will completely be reacted. There will react 0.00375 moles NaOH. There will remain 0.004575 - 0.00375 = 0.000825 moles NaOH

Step 5: Calculate molarity of NaOH

Molarity NaOH = moles NaOH / volume

Molarity NaOH = 0.000825 moles / 0.0555 L

Molarity NaOH = 0.0149 M

Step 6: Calculate pOH

pOH = -log [OH-]

pOH = -log (0.0149)

pOH = 1.83

The pOH = 1.83

6 0
3 years ago
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