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levacccp [35]
3 years ago
10

The electron domain and molecular geometry of NF₃ are ________.

Chemistry
1 answer:
Anna35 [415]3 years ago
8 0

Answer:

The electron domain and molecular geometry of NF₃ are option b

Explanation:

First of all, think the total valence electrons of each element.

N : 5

F: 7, but we have 3, so 7.3 = 21

Total: 26 e⁻

Now let's draw a scheme

             F   ----  N  ----  F

                          |

                         F

We have to put 26 e⁻ around the elements, so 6 e⁻ are been used for the bonds N-F, so now, there are 20 e⁻  to add. As the F, have used 1 e⁻ to form the bond, there are 6 more, around. Each fluorine which has 7 e⁻,  shares 1e⁻ with the N, to complete the octet rule.

So, there are still 2e⁻ to add. They will be above the N and they are free. That's why the molecular geometric is trigonal, and the electronic geeometry is tetrahedral because the non-binding electron pair of N

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7 0
2 years ago
Plz help! :) :D I will mark you as BRAINLIEST!!!
nadezda [96]

Answer:

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Explanation:

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8 0
3 years ago
what information can a foliated metamorphic rock provide you about the conditions under which it formed
uysha [10]
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3 years ago
Define electron affinity
LekaFEV [45]
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8 0
2 years ago
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Marrrta [24]
<h3><u>Answer</u>;</h3>

= 226 Liters of oxygen

<h3><u>Explanation</u>;</h3>

We use the equation;

LiClO4 (s) → 2O2 (g) + LiCl, to get the moles of oxygen;

Moles of  LiClO4;

(500 g LiClO4) / (106.3916 g LiClO4/mol)

= 4.6996 moles

Moles of oxygen;

But, for every 1 mol LiClO4, two moles of O2 are produced;

= 9.3992 moles of Oxygen

V = nRT / P

= (9.3992 mol) x (8.3144621 L kPa/K mol) x (21 + 273) K / (101.5 kPa)

= 226 L of oxygen

5 0
3 years ago
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