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3 years ago

8

Calculate the mass of 6.45 x 10^22 atoms of carbon

1 answer:

ludmilkaskok [199]3 years ago

5 0

Answer:

m(C)=?

N(C)=6,45*10²²atom

N= n*Na n(C)=N/Na n(C)= 6,45*10²²/6,023*10²³ N(C)=0,1075mol

M(C)=12 n=m/M m(C)=0,1075mol*12g/mol m(C)=1,29g

Explanation:

We use two types of formulas: N=n*Na and n=m/M

N- number of atoms

Na- number of Avogadro 6,023*10²³

n- quantity of substance

m-mass of the substance

M-molar mass (for carbon is 12, we can find it in the Periodic sistem)

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If the energy difference between two electronic states is 214.68 kJ / mol , calculate the frequency of light emitted when an ele

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${\qquad\qquad\huge\underline{{\sf Answer}}}$

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Read 2 more answers

2 CuCl2 + 4 KI → 2 CuI + 4 KCl + I2

Margaret [11]

Answer: 6.75 moles

Explanation:

This is a simple stoichiometry proboe. that I would set up like this:

(13.5 moles CuCI2) (1 mol I2 / 2 moles CuCi2)

That means you all you have to do for this problem is divide by 2 and cancel out the unit moles CuCI2, which leaves you with 6.75 moles I2.

Hope this helps :)

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