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Radda [10]
3 years ago
8

Calculate the mass of 6.45 x 10^22 atoms of carbon​

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
5 0

Answer:

m(C)=?

N(C)=6,45*10²²atom

N= n*Na      n(C)=N/Na    n(C)= 6,45*10²²/6,023*10²³   N(C)=0,1075mol

M(C)=12   n=m/M     m(C)=0,1075mol*12g/mol       m(C)=1,29g

Explanation:

We use two types of formulas: N=n*Na and n=m/M

N- number of atoms

Na- number of Avogadro 6,023*10²³

n- quantity of substance

m-mass of the substance

M-molar mass (for carbon is 12, we can find it in the Periodic sistem)

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Answer:

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Explanation:

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according to the molar ratio

1 mol of CuCO₃ decomposes to form 1 mol of CO₂

therefore 0.364 mol of  CuCO₃ decomposes to form 0.364 mol of CO₂

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Explanation :

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Thus, the edge length is equal to the sum of 2 radius of Cl⁻ ion and 2 radius of Na⁺ ion.

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Thus, the relation will be:

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