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3 years ago

Based on the information in the passage, what is true of gases?

Chemistry

2 answers:

prisoha [69]3 years ago

5 0

Answer: A. Some, but not all, gases are harmful to humans.

Explanation: Some toxic gases:

carbon monoxide
chlorine
nitrogen dioxide

Harmless gases:

compressed air
nitrogen
helium

UkoKoshka [18]3 years ago

3 0

The answer is A because some gases are dangerous and some aren’t

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resistor has a resistance of 1.8 W. How much current passes through the resistor if there is a potential difference of 3.0 V acr

valentinak56 [21]

Answer:

4.0 V?

Explanation

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3 years ago

Which is an advantage of selling plant fertilizer as a powder rather than as a liquid?

elena55 [62]

Answer:A

Explanation: because i saw the sheet

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3 years ago

3Al + 3NH4ClO4 → Al2O3 + AlCl3 + 3NO + 6H2O How many moles of AlCl3 are produced?

zhuklara [117]

Answer: 1 mol of $AlCl_3$ will be produced from this reaction.

Explanation: Reaction follows,

$3Al+3NH_4ClO_4\rightarrow Al_2O_3+AlCl_3+3NO+6H_2Oc$

As seen from the balanced chemical equation above, we get

For every 3 moles of Aluminium and 3 moles of $NH_4ClO_4$ , 1 mole of $Al_2O_3$ is formed.

For every 3 moles of Aluminium and 3 moles of $NH_4ClO_4$ , 1 mole of $AlCl_3$ is formed.

For every 3 moles of Aluminium and 3 moles of $NH_4ClO_4$ , 3 moles of $NO$ is formed.

For every 3 moles of Aluminium and 3 moles of $NH_4ClO_4$ , 6 moles of $H_2O$ is formed.

7 0

4 years ago

Read 3 more answers

Molybdenum (Mo) has a body centered cubic unit cell. The density of Mo is 10.28 g/cm3. Determine (a) the edge length of the unit

ser-zykov [4K]

Answer:

For a: The edge length of the unit cell is 314 pm

For b: The radius of the molybdenum atom is 135.9 pm

Explanation:

For a:

To calculate the edge length for given density of metal, we use the equation:

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

$\rho$ = density = $10.28g/cm^3$

Z = number of atom in unit cell = 2 (BCC)

M = atomic mass of metal (molybdenum) = 95.94 g/mol

$N_{A}$ = Avogadro's number = $6.022\times 10^{23}$

a = edge length of unit cell =?

Putting values in above equation, we get:

$10.28=\frac{2\times 95.94}{6.022\times 10^{23}\times (a)^3}\\\\a^3=\frac{2\times 95.94}{6.022\times 10^{23}\times 10.28}=3.099\times 10^{-23}\\\\a=\sqrt[3]{3.099\times 10^{-23}}=3.14\times 10^{-8}cm=314pm$

Conversion factor used: $1cm=10^{10}pm$

Hence, the edge length of the unit cell is 314 pm

For b:

To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:

$R=\frac{\sqrt{3}a}{4}$

where,

R = radius of the lattice = ?

a = edge length = 314 pm

Putting values in above equation, we get:

$R=\frac{\sqrt{3}\times 314}{4}=135.9pm$

Hence, the radius of the molybdenum atom is 135.9 pm

4 0

3 years ago

What has 6 valence electrons and 16 protons and ends withthe letter "r"

zmey [24]

Answer:

Sulphur

Explanation:

Sulphur(S) is the Sixteenth element of the periodic table and it has an electronic configuration of 2,8,6. This means it has six electrons in its outermost shell( valence electrons).

Sulphur has sixteen(16) protons which is equal to the atomic number which is also sixteen. Sulphur ends with the letter ‘r’. All the descriptions of the element are satisfied and it validates Sulphur.

4 0

3 years ago