Answer: S8(s) + 8O2(g) → 8SO2(g) ΔH = -2368 kJ a.
Answer:
CuSO4(aq)
Explanation:
The aqueous form of copper sulfate will conduct electricity.
The Solid form will not be a good conductor.
C₅H₁₂ will not conduct electricity
CO₂ will not conduct electricity
- Copper sulfate is an ionic compound
- In aqueous solutions or molten forms, ionic compounds can conduct an electric current using free mobile ions as carriers.
- This way, they are electrolytes.
- In solid state, the ions are arranged into a crystal lattice and will not conduct a current of electricity.
Answer:MORE THAN 50 STUDIES WERE CONDUCTED
THE US PUBLIC HEALTH SERVICE WAS RESPONSIBLE FOR PART OF THE STUDY
Explanation: Just completed the assignment Egenuity , i hope this helps .
Answer:
Hydrosulfuric acid will act as limiting reactant.
Explanation:
Given data:
Mass of iron(III) chloride = 3243.0 g
Mass of hydrosulfuric acid = 511.8 g
Limiting reactant = ?
Solution:
Chemical equation:
2FeCl₃ + 3H₂S → Fe₂S₃ + 6HCl
Number of moles of iron(III) chloride:
Number of moles = mass/molar mass
Number of moles = 3243.0 g/ 162.2 g/mol
Number of moles = 20 mol
Number of moles of hydrosulfuric acid:
Number of moles = mass/molar mass
Number of moles = 511.8 g/ 34.1 g/mol
Number of moles = 15 mol
Now we will compare the moles of both reactant with products
FeCl₃ : Fe₂S₃
2 : 1
20 : 1/2 ×20 = 10
FeCl₃ : HCl
2 : 6
20 : 6/2 ×20 = 60
H₂S : Fe₂S₃
3 : 1
15 : 1/3 ×15 = 5
H₂S : HCl
3 : 6
15 : 6/3 ×15 = 30
Hydrosulfuric acid producing less number of moles of product thus, it will act as limiting reactant.
