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algol [13]
4 years ago
13

A quadrilateral has two angles that measure 31° and 249°. The other two angles are in a ratio of 3:17. What are the measures of

those two angles?
Mathematics
2 answers:
dsp734 years ago
7 0

Step-by-step explanation:

<em>Given </em><em>1st </em><em>angle </em><em>=</em><em> </em><em>3</em><em>1</em><em>°</em><em> </em><em>and </em><em>2nd </em><em>angle </em><em>=</em><em> </em><em>2</em><em>4</em><em>9</em><em>°</em><em> </em>

<em>Let </em><em>the </em><em>remaining </em><em>two </em><em>angles </em><em>be </em><em>3x </em><em>and </em><em>17x</em>

<em>3</em><em>1</em><em>°</em><em> </em><em>+</em><em> </em><em>2</em><em>4</em><em>9</em><em>°</em><em> </em><em>+</em><em> </em><em>3x </em><em>+</em><em> </em><em>17x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em><em><</em><em> </em><em>Being </em><em>sum </em><em>of </em><em>angles </em><em>of </em><em>quadrilateral </em><em>></em>

<em>2</em><em>8</em><em>0</em><em>°</em><em> </em><em>+</em><em> </em><em>20x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em>

<em>20x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em><em> </em><em>-</em><em> </em><em>2</em><em>8</em><em>0</em><em>°</em>

<em>20x </em><em>=</em><em> </em><em>8</em><em>0</em><em>°</em>

<em>Therefore </em><em>x=</em><em> </em><em>4</em><em>°</em>

<em>Now </em>

<em>Measurements </em><em>of </em><em>both </em><em>angles</em>

<em>3x </em><em>=</em><em> </em><em>3</em><em> </em><em>*</em><em> </em><em>4</em><em>°</em><em>=</em><em> </em><em>12°</em>

<em>17x </em><em>=</em><em> </em><em>1</em><em>7</em><em>*</em><em>4</em><em>°</em><em> </em><em>=</em><em> </em><em>6</em><em>8</em><em>°</em>

Mnenie [13.5K]4 years ago
5 0

Answer:

Step-by-step explanation:

We first need to find the measure of the other 2 angles.  The angles of a quadrilateral all add up to equl 360, so:

360 - 249 - 31 = 80

The other 2 angles add up to equal 80 degrees.  If these angles exist in a 3:17 ratio, then algebraically,

3x + 17x = 80 and

20x = 80 so

x = 4.  That means that one angle is 3(4) = 12 and the other angle is 17(4) = 68.

249 + 31 + 12 + 68 = 360.

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OLga [1]

Answer:

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Step-by-step explanation:

8 0
3 years ago
luke jogged a total of 56.5 miles last week. if luke jogged the same distance,d, each day for 3 days and half that distance on e
Leokris [45]
The algebraic equation used to answer this question is:
3d + 4(1/2d) = 56.5
This is because he ran d, the distance, three times that week. For the rest of the four days, he ran 1/2 the distance, or half d.
To find the answer, you first distribute:
3d + 2d = 56.5
Add like terms:
5d = 56.5
Divide both side by 5:
5d/5 = 56.5/5
d = 11.3
On the first three days, Luke jogged 11.3 miles. On the remaining days, where he jogged 1/2d, Luke jogged 5.65 miles.
Hope this helps!
3 0
4 years ago
U guys are mean and never answer my questions, like i paid for no one to answer my question
Sav [38]

Answer:

Step-by-step explanation:

You have no grounds for making a statement like that.  There are a variety of reasons why you might not get immediate answers.  Be patient.

I will do the second part of this question (finding the first three numbers):

a(4) = a(3)*(-3) + 2 = -148, so a(3)*(-3) = -150 and a(3) = -50

a(3) = 50

a(2) = a(3)*(-3) + 2 = 50, so -3*a(3) = 48 and a(d) = -16

a(1) = a(2)*(-3) + 2 = -16, so a(2)*(-3) = -18 and a(1) = 6

The procedure for finding a(5), a(6) and a(7) is exactly the same.

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3 years ago
a recipe for lemonade calls for 1 cup of sugar and 5 cups of water. How much sugar is used per cup of water
lys-0071 [83]
0.20 of a cup of sugar is used per cup of water
8 0
4 years ago
Given f(x) = the quantity of 3x minus 1, divided by 2 , solve for f−1(4)
hichkok12 [17]
<span>f(x)=(<span><span>3x−1)/</span>2<----Starter </span></span>
y = (3x-1)/2
switch x and y
x = (3y-1)/2
2x = 3y-1
2x+1 =3y
y = 2/3*x + 1/3 
f^(-1) (x) = 2/3*x + 1/3 
f^(-1) (4) = 2/3*4 + 1/3 = 8/3 + 1/3 = 9/3 = 3

I hope this helps. ;)
3 0
3 years ago
Read 2 more answers
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