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zhannawk [14.2K]
3 years ago
8

I'm doing an online course to study for a test. Can someone please explain how to do this? :(

Mathematics
2 answers:
Leona [35]3 years ago
8 0
Hi there

This is how you read the question: What is the cube root of 64.
To answer this question ask yourself what number multiplied by itself three times gives you the answer 64?
1*1*1=1
2*2*2=8
3*3*3=27
4*4*4=64
YAY! that means the answer is 4. 

Hope this helps.
And you give me the brainliest answer.
Thanks
aliya0001 [1]3 years ago
3 0
The cube root is 4

4x4x4 is 64...

Hope this helps and you rate me good e
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(5.2x + 36.4x + 52)/ (2.6x +13)
g100num [7]
Combine like terms in the first set and get
41.6x +52/2.6x + 13

I got 16x + 4
4 0
3 years ago
4. At Eagle Rock High School, the probability that a student takes theatre and choir is 0.052.
aleksklad [387]

Answer:

B

Step-by-step explanation:

Conditional probability is:

P(A given B) = P(A and B) / P(B)

Here, P(A and B) = 0.052 and P(B) = 0.17:

P(A given B) = 0.052 / 0.17

P(A given B) = 0.306

6 0
3 years ago
Which is the standard form of the equation of the parabola that has a vertex of (3, 1) and a directric of x = -2?
vagabundo [1.1K]
Check the picture below.  So,the parabola looks like so, notice the distance "p". since the parabola is opening to the right, then "p" is positive, thus is 5.

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
\boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}})} \\\\
(x-{{ h}})^2=4{{ p}}(y-{{ k}}) \\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\

\bf -------------------------------\\\\
\begin{cases}
h=3\\
k=1\\
p=5
\end{cases}\implies (y-1)^2=4(5)(x-3)\implies (y-1)^2=20(x-3)
\\\\\\
\cfrac{1}{20}(y-1)^2=x-3\implies \boxed{\cfrac{1}{20}(y-1)^2+3=x}

8 0
3 years ago
Read 2 more answers
Solve triangle ABC with m
Irina18 [472]
Yeah I’ll get right on that.
3 0
3 years ago
Which answer is correct? It wouldn’t let me click mathematics btw
Bad White [126]
6)
KM bisects on <NKL so m<MKN = m<MKL = 3x + 5

2(m<MKL) + m<JKN = 180
2(3x+5) + 8x + 2 = 180
6x + 10 + 8x + 2 = 180
14x + 12 = 180
14x = 168
    x = 12

so 
 m<MKN = m<MKL = 3x + 5 = 3(12) + 5 = 36 + 5 = 41

answer
b. 41

7)

2 supplementary has sum = 180
x + x + 14 = 180
2x + 14 = 180
2x = 166
  x = 83
  x + 14 = 83 + 14 = 97

2 angles are 83 and 97

answer
b. 83, 97
7 0
3 years ago
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