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3 years ago

I'm doing an online course to study for a test. Can someone please explain how to do this? :(

Mathematics

2 answers:

Leona [35]3 years ago

8 0

Hi there

This is how you read the question: What is the cube root of 64.
To answer this question ask yourself what number multiplied by itself three times gives you the answer 64?
1*1*1=1
2*2*2=8
3*3*3=27
4*4*4=64
YAY! that means the answer is 4.

Hope this helps.
And you give me the brainliest answer.
Thanks

aliya0001 [1]3 years ago

3 0

The cube root is 4

4x4x4 is 64...

Hope this helps and you rate me good e

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Uh i need help with those 3, will give brainliest, thanks!

rusak2 [61]

Answer:

26 = G. 27 = A. 28 = J

Step-by-step explanation:

26} A Nickle = 5 cents. A Dime = 10 Cents.

Way #1: 5+5+5+5+5+5 = 30

Way #2: 10 + 10 + 10 = 30

Way #3: 10 + 5 + 5 + 5 + 5 = 30

Way #4: 10+ 10+ 5 + 5 = 30

27} Pennies = 1 Cent. Nickels = 5 Cents. Dimes = 10 cents.

Way #1: 1+1+1+1+1+5+ 10 = 20

28} Pennies = 1 Cent. Nickels = 5 Cents. Dimes = 10 Cents.

Way #1: 10+5+1+1 = 17

Way #2: 5+5+5+11 = 17

Way #3: 1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1 = 17

Way #4: 1+1+1+1+1+1+1+10 = 17

Way #5: 5+1+1+1+1+1+1+1+1+1+1+1+1 = 17

5 0

2 years ago

a jar contains 6 jellybeans, 4 green jellybeans, and 4 blue jelly beans. if we choose a jellybean, then another without putting

posledela

Probability first one is blue is 4/6+4+4=4/14
the second one is also blue is 4-1/6+4+4-1=3/13

The probability of getting blue both time is 4/14*3/13=12/182=0.0659=6.59%

Answer:
0.0659 or 6.59%

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2 years ago

Let $f(x)$ be a function defined for all positive real numbers satisfying the conditions $f(x) > 0$ for all $x > 0$ and $f

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Suppose we choose $x=1$ and $y=\dfrac12$ . Then

$f(x-y)=\sqrt{f(xy)+1}\implies f\left(\dfrac12\right)=\sqrt{f\left(\dfrac12\right)+1}\implies f\left(\dfrac12\right)=\dfrac{1+\sqrt5}2$

Now suppose we choose $x,y$ such that

$\begin{cases}x-y=\dfrac12\\\\xy=2009\end{cases}$

where we pick the solution for this system such that $x>y>0$ . Then we find

$\dfrac{1+\sqrt5}2=\sqrt{f(2009)+1}\implies f(2009)=\dfrac{1+\sqrt5}2$

Note that you can always find a solution to the system above that satisfies $x>y>0$ as long as $x>\dfrac12$ . What this means is that you can always find the value of $f(x)$ as a (constant) function of $f\left(\dfrac12\right)$ .

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