Solution:
As given Square L M NO is dilated by a scale factor of two about the center of the square to create square L'M'N'O'.
Original line of Dilation = Along P Q
New Dilated line = P'Q'
As scale factor > 1
1. Image Size > Pre image size
2. The two images will be similar.
3. Length of Dilated Line P' Q' = 2 × Length of PQ
As you can see from the diagram drawn below, Dilated line P'Q' will contain the point P and Q.
All four points P,Q,Q',P' are collinear , lie in the same line.
Option (2) dilated line P'Q' will contain the points P and Q is true.
Answer:
d. 89°
Step-by-step explanation:
The given measure of the angles formed are;
m∠AED = 48°, m
= 175°
According to circle theorem, the angle formed by a chord and a tangent of a circle is given by half of the measure of the arc intercepted by the chord in the direction of the angle;
Therefore;
m∠AED = (1/2) × m
= 48°
∴ m
= 2 × 48° = 96°
m∠AEF = (1/2) × m
m
+ m
= 360° (angle round a circle)
∴ m
= 360° - m
= 360° - 96° = 264°
m
= m
+ m
∴ m
= m
- m
= 264° - 175° = 89°
m
= 89°.
Answer:

Step-by-step explanation:
The given cylindrical equation is

Multiply both sides by r.
.... (1)
The required formulas are

Substitute
in equation (1).


Add 1 on both sides.

![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)
It is the equation of a circle centered at (0,1) with radius 1.
Therefore, the equation in rectangular coordinates is
.
I think you forgot to put the image in the question