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Marizza181 [45]
3 years ago
11

The diagonals of a kite _____.

Mathematics
1 answer:
Vikentia [17]3 years ago
5 0

Answer:

A. Meet at a right angle.

Step-by-step explanation:

We should know the properties of kite.

(1) The diagonals of a kite meet at a right angle.

(2) Kites have exactly one pair of opposite angles that are congruent.

Therefore, the answer is A. Meet at a right angle.

Thank you.

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Simplify and then classify by degree and number of terms<br> 2x+3x^2(4x-5)
Delicious77 [7]

Answer:

2x + 3x^2 (4x - 5)

2x + 12x^3 - 15x^2

12x^3 - 15x^2 + 2x

Degree - 3

Terms - 3 (Trinomial)

<h3>Lets explore more - </h3>

  • The degree of a polynomial is the highest power of its variable
  • Degree represents the no. of zeros of the polynomial

  • <em><u>Linear</u></em><em><u> </u></em> - Degree 1
  • <em><u>Quadrati</u></em><em><u>c</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em>Degree 2
  • <em><u>Cubic</u></em><em><u> </u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em>Degree 3
  • <em><u>Biquadratic</u></em><em><u> </u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em>Degree 4

  • Terms - Classification of polynomial On the basis of terms

  1. monomial - polynomial which has only 1 term
  2. Binomial - Polynomial which has 2 terms
  3. Trinomial - Polynomial which has 3 terms
5 0
3 years ago
Read 2 more answers
If square LMNO is dilated by a scale factor of two about the center of the square to create square L'M'N'O', dilated line P'Q' w
Genrish500 [490]

Solution:

As given Square L M NO is dilated by  a scale factor of two about the center of the square to create square L'M'N'O'.

Original line of Dilation = Along P Q

New Dilated line = P'Q'

As scale factor > 1

1. Image Size > Pre image size

2. The two images will be similar.

3. Length of Dilated Line P' Q' = 2 × Length of PQ

As you can see from the diagram drawn below, Dilated line P'Q'  will contain the point P and Q.

All four points P,Q,Q',P' are collinear , lie in the same line.

Option (2) dilated line P'Q' will contain the points P and Q is true.



6 0
3 years ago
Read 2 more answers
NEED THE ANSWER PLEASE
Alexus [3.1K]

Answer:

d. 89°

Step-by-step explanation:

The given measure of the angles formed are;

m∠AED = 48°, m\widehat{AG} = 175°

According to circle theorem, the angle formed by a chord and a tangent of a circle is given by half of the measure of the arc intercepted by the chord in the direction of the angle;

Therefore;

m∠AED = (1/2) × m\widehat{ABE}  = 48°

∴ m\widehat{ABE} = 2 × 48° = 96°

m∠AEF = (1/2) × m\widehat{AGE}

m\widehat{ABE} + m\widehat{AGE} = 360° (angle round a circle)

∴ m\widehat{AGE} = 360° - m\widehat{ABE} = 360° - 96° = 264°

m\widehat{AGE} = m\widehat{AG} + m\widehat{EG}

∴ m\widehat{EG} = m\widehat{AGE} - m\widehat{AG} = 264° - 175° = 89°

m\widehat{EG} = 89°.

5 0
3 years ago
Find an equation in rectangular coordinates for the cylindrical equation r = 2sintheta
frutty [35]

Answer:

x^2+(y-1)^2=1

Step-by-step explanation:

The given cylindrical equation is

r=2\sin \theta

Multiply both sides by r.

r^2=2r\sin \theta           .... (1)

The required formulas are

x=r\cos \theta,y=r\sin \theta,r^2=x^2+y^2

Substitute r\sin \theta =y,r^2=x^2+y^2 in equation (1).

x^2+y^2=2y

x^2+y^2-2y=0

Add 1 on both sides.

x^2+(y^2-2y+1)=1

(x-0)^2+(y-1)^2=1^2                    [\because (a-b)^2=a^2-2ab+b^2]

It is the equation of a circle centered at (0,1) with radius 1.

Therefore, the equation in rectangular coordinates is x^2+(y-1)^2=1.

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3 years ago
The hanger image below represents a balanced equation.
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