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3 years ago

The diagonals of a kite _____.

Mathematics

1 answer:

Vikentia [17]3 years ago

5 0

Answer:

A. Meet at a right angle.

Step-by-step explanation:

We should know the properties of kite.

(1) The diagonals of a kite meet at a right angle.

(2) Kites have exactly one pair of opposite angles that are congruent.

Therefore, the answer is A. Meet at a right angle.

Thank you.

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In Drosophila, the genes for withered wings (whd), smooth abdomen (sm) and speck body (sp) are located on chromosome 2 and are s

boyakko [2]

Answer:

The number of expected double crossover progeny is 47.275

To the nearest whole number 47

Step-by-step explanation:

Consider the provided information.

The distance between withered wings (whd) and smooth abdomen (sm) is 30.5,

That means the probability of crossover between them is 0.305.

The distance between smooth abdomen (sm) and speck body (sp) is 15.5,

That means the probability of crossover between them is 0.155

The resulting phenotypically wild-type females were mated with males that had the mutant phenotype for all three traits,

That means the expected frequency of double crossover progeny will be:

0.305×0.155 = 0.047275

It is given that they producing 1000 offspring, therefore,

0.047275×1000 = 47.275

The number of expected double crossover progeny is 47.275

To the nearest whole number 47

3 0

3 years ago

-1+8v=2+8v what is the value of v?

Nesterboy [21]

Answer: There are no solutions.

Step-by-step explanation:

6 0

3 years ago

Let x be a random variable representing dividend yield of Australian bank stocks. We may assume that x has a normal distribution

kotegsom [21]

Answer:

a) 0.025 level of significance

The calculated t - value t = 2.88 > 3.58 at 0.025 level of significance

Therefore null hypothesis is rejected

The data indicate that the dividend yield of all Australian bank stocks is higher than 7.9%

Step-by-step explanation:

Step(i):-

Let 'x' has a normal distribution

Given sample size 'n' =11

Mean of the sample (x⁻) = 9.89% = 0.0989

Standard deviation of the sample (s) = 2.3% = 0.023

Mean of the Population ' μ' = 7.9% = 0.079

Step(ii):-

Null hypothesis:H₀:' μ' = 0.079

Alternative Hypothesis :μ' > 0.079

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

$t = \frac{0.0989-0.079}{\frac{0.023}{\sqrt{11} } }$

t = 2.8840

Degrees of freedom

ν = n-1 = 11-1 =10

Level of significance

$t_{\frac{\alpha }{2} } = t_{\frac{0.05}{2} } = t_{0.025}$

$t_{0.025} , 10 = 3.5814$

Step(iii):-

The calculated t - value t = 2.88 > 3.58 at 0.025 level of significance

Therefore null hypothesis is rejected

The data indicate that the dividend yield of all Australian bank stocks is higher than 7.9%

7 0

3 years ago

Solve the question and check the solution. Express numbers as integers or simplified fractions. 5(m+5)=7m+9

Yanka [14]

Answer:

m = 8

Step-by-step explanation:

5(m+5)=7m+9 (distribute & evaluate parenthesis)

5(m)+5(5)=7m+9

5m + 25 = 7m + 9 (move all m-terms to one side and constants to the other)

5m - 7m = 9 - 25 (evaluate both sides)

-2m = -16 (divide both sides by -2)

m = (-16) / ( -2) = 8

7 0

3 years ago

If it takes 15 min to load 3 racks of buns, how many hours will it take to load 36 racks?

GrogVix [38]

Set up the equation of two ratios:

3 racks 36 racks
----------- = --------------
15 min x

Solve this for x: 3x =540; x = 180 minutes, or 3 hours

6 0

3 years ago

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