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inn [45]
2 years ago
6

Which statement best describes the main benefit to organisms that reproduce sexually?

Chemistry
2 answers:
Reil [10]2 years ago
7 0

Answer:

b

Explanation:

8090 [49]2 years ago
5 0

Answer:

B. They will conserve energy during reproduction

Explanation:

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They dump large amounts of rainwater that causes flooding. *
IgorC [24]
Answer =Tsunamis because they flood places and areas
3 0
3 years ago
Read 2 more answers
Which of the following structures are accessory structures of the digestive system?
professor190 [17]

the pancreas and the liver

7 0
3 years ago
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Fill in the left side of this equilibrium constant equation for the reaction of benzoic acid (HC_6H_5CO_2) with water.
il63 [147K]

Answer:

[C₆H₅COO⁻][H₃O⁺]/[C₆H₅COOH] = Ka

Explanation:

The reaction of dissociation of the benzoic acid in water is given by the following equation:

C₆H₅-COOH + H₂O  ⇄  C₆H₅-COO⁻  +  H₃O⁺    (1)

The dissociation constant of an acid is the measure of the strength of an acid:

HA ⇄ A⁻ + H⁺        (2)

K_{a} = \frac{[A^{-}][H^{+}]}{[HA]}      (3)

<em>Where the dissociation constant of the acid (Ka) is equal to the ratio of the concentration of the dissociated forms of the acid, [A⁻][H⁺], and the concentration of the acid, [HA].     </em>

So, starting from the equations (2) and (3), the constant equation for the dissociation reaction of benzoic acid in water, of the equation (1), is:

K_{a} = \frac{[C_{6}H_{5}COO^{-}][H_{3}O^{+}]}{[C_{6}H_{5}COOH]}

I hope it helps you!          

6 0
3 years ago
I NEED HELP ASAP !
Lana71 [14]

Answer:

1.

643.21g  1 mol  6.022^23

262.87 g   1 mol

= 1.4735E24     [Mg3(PO4)2]

2.

4.061x10^24          1mol                22.4 (L)  

6.022^23       1mol

= 151 liters H2O2

3.

479.3g   1 mol   6.022^23

18.02g    1mol

= 1.60E25 H20 atoms

4.

80.34L   1mol       164.1

22.4L       1mol

588.6g   Ca(NO3)2

5.

893.7g   1mol       22.4

44.01g   1mol

= 427 L CO2 or 427.4

6.

5.39 x 10^25     1mol     78.01

6.022^23    1mol

= 6980g Al(OH)3

hope this helps!! :)

8 0
2 years ago
The air bags in cars are inflated when a collision triggers the explosive, highly exothermic decomposition of sodium azide (NaN3
Oksanka [162]

Answer : The mass of NaN_3 required is, 166.4 grams.

Explanation :

First we have to calculate the moles of nitrogen gas.

Using ideal gas equation:

PV=nRT

where,

P = Pressure of N_2 gas = 1.00 atm

V = Volume of N_2 gas = 113 L

n = number of moles N_2 = ?

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of N_2 gas = 85^oC=273+85=358K

Putting values in above equation, we get:

1.00atm\times 113L=n\times (0.0821L.atm/mol.K)\times 358K

n=3.84mol

Now we have to calculate the moles of sodium azide.

The balanced chemical reaction is,

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

From the balanced reaction we conclude that

As, 3 mole of N_2 produced from 2 mole of NaN_3

So, 3.84 moles of N_2 produced from \frac{2}{3}\times 3.84=2.56 moles of NaN_3

Now we have to calculate the mass of NaN_3

\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3

Molar mass of NaN_3 = 65 g/mole

\text{ Mass of }NaN_3=(2.56moles)\times (65g/mole)=166.4g

Therefore, the mass of NaN_3 required is, 166.4 grams.

3 0
3 years ago
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