All categories

3 years ago

What are the three subatomic particles that make up an atom

Physics

1 answer:

Harrizon [31]3 years ago

5 0

Answer:

Proton, neutron, electron

Explanation:

The atom consists of a nucleus, where almost all the mass is concentrated, and electrons orbiting around the nucleus.

The nucleus consists of two types of particles:

- Proton: it has a mass of $1.6726\cdot 10^{-27} kg$ , and a positive electric charge of +e ( $1.6\cdot 10^{-19}C$ )

- Neutron: it has a mass of $1.6749 \cdot 10^{-27}kg$ , and it has no electric charge

The third particle that makes an atom is the electron, that orbit around the nucleus:

- Electron: it has a mass of $9.1094\cdot 10^{-31}kg$ , and it has a negative electric charge of -e ( $-1.6\cdot 10^{-19}C$ )

You might be interested in

Activity

vodka [1.7K]

Your welcome LOL plz like

5 0

3 years ago

Which career professionals are part of the Architecture and Construction career cluster? Check all that apply.

oksian1 [2.3K]

Answer:

A,B,D,E,F

Explanation:

I took the test for yall.

3 0

3 years ago

Which technology is most efficient in mapping large areas of the ocean floor?

qaws [65]

''Sonar'' is the answer.

7 0

3 years ago

Electrons are accelerated in the picture tube of a television through potential difference of 8.00 * 10 ^ 3 V. (Use the values q

maria [59]

Answer:

$\lambda=1.37\times 10^{-11}\ m$

Explanation:

Give that,

The potential difference of the electrons, $V=8\times 10^{3}\ V$

We need to find the wavelength of the electrons.

Using the conservation of energy,

$2meV=\dfrac{h^2}{\lambda^2}\\\\\lambda=\sqrt{\dfrac{h^2}{2meV}}$

Put all the values,

$\lambda=\sqrt{\dfrac{(6.63\times 10^{-34})^2}{2\times 9.1\times 10^{-31}\times 1.6\times 10^{-19}\times 8\times 10^3}}\\\\\lambda=1.37\times 10^{-11}\ m$

So, the wavelength of the electrons is $1.37\times 10^{-11}\ m$ .

7 0

3 years ago

Sammy squirrel is steering his boat at a heading of 327 degree at 18mph. The current is flowing at 4mph at a heading of 60 degre

Tanya [424]

Answer:

59.97 º at 18.23 mph

Explanation:

To find Sammy's course you have to add the two velocities (vectors), 18 mph 327º and 4 mph 60º.

To add the two vectors analytically you decompose each vector into their vertical and horizontal components.

1. 18 mph 327º

Horizontal component: 18 mph × cos (327º) = 15.10 mph

Vertical component: 18 mph × sin (327º) = - 9.80 mph

Vector notation:

$15.10\hat i-9.80\hat j$

2. 4 mph 60º

Horizontal component: 4 mph × cos (60º) = 2.00 mph

Vertical component: 4 mph × sin (60º) = 3.46 mph

Vector notation:

$2.00\hat i+3.46\hat j$

3. Addition:

You add the corresponding components:

$15.10\hat i-9.80\hat j+2.00\hat i+3.46\hat j\\ \\ 17.10\hat i-6.34\hat j$

To find the magnitude use Pythagorean theorem:

$\sqrt{17.1^2+6.34^2}= 18.23$

4. Direction:

Use the tangent ratio:

$tan(\alpha )=opposite/adjacent=3.46/2.00=1.73$

Find the inverse:

arctan (1.73) ≈ 59.97º

5 0

3 years ago