The magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s
The rotating equivalent of linear momentum in physics is called angular momentum. Because it is a conserved quantity—the total angular momentum of a closed system stays constant—it is significant in physics. Both the direction and the amplitude of angular momentum are preserved.
Given the density of air to be 1.29 kg/m3 and a wind speed of 73.0 mi/h
We have to find the magnitude of the angular momentum
Let,
ρ = Density of air = 1.29 kg/m^3
v = Speed of wind = 73.0 mi/h = 0.032 km/s
M = angular momentum of air
Let the volume of air be 1 m^3
Mass = Volume x ρ = 1 x 1.29 = 1.29 kg
Momentum = M = mass x velocity
Momentum = 1.29 x 0.0032
Momentum = 4.128 x 10^(-3) kg·m^2/s
Hence the magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s
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Answer:
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Explanation:
A man walking at the rate of 5 km/hr. crosses a bridge in 15 minutes. The length of the bridge (in meters) is:
[A]1000 m
[B]1250 m
[C]600 m
[D]750 m
1250 m
Speed of the man = 5 km/hr

Time taken to cross the bridge = 15 minutes
Length of the bridge = Speed  Time

Hence option [B] is the right answer.
Answer:
Explanation:
Given
mass of balls 

angular velocity 
Length of Rod 
Tension in the Second half of rod



For First Part





Answer:
A building where the boy is on the 12 floor
Explanation:
The equation of the height or position takes into account the initial conditions.
So the general equation is
x(t) = at+c
When you solve with the initial conditions t=0 you will find the position at the begining, so this is c the constant.
in our initial equation we have 95 as the constant. and this is a equation to find height so the initial height is 95feets.
Now a common building has a distance of 7.5 feet between every floor.
You divide 95 by 7.5 and you will find 12.6
It is a reactant, as it, with water and CO2 reacts to form the products.