1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Grace [21]
3 years ago
14

A 95% confidence interval estimate for a population mean u is determined to be 75.38 to 86.52. If the confidence level is reduce

d to 90%, the confidence interval for u A. becomes wider B. remains the same C. becomes narrower D.. none of the above answers is correct
Mathematics
2 answers:
PolarNik [594]3 years ago
6 0

Answer:

C. becomes narrower

Step-by-step explanation:

If the confidence level is reduced from 95% to 90%, then, the confidence interval for u becomes narrower, i.e., we are less sure that the true value of u is contained inside the new interval. With a 95% confidence interval there is a probability of 0.95 that the parameter u is inside the interval and with a 90% confidence interval there is a probability of 0.90 that the parameter u is inside the interval.

Mars2501 [29]3 years ago
6 0

Answer: the correct option is C

Step-by-step explanation:

The 95% confidence interval for the population mean is determined to be 75.38 to 86.52. If the confidence interval is reduced to 90%, the the confidence interval for u will become narrower. This is because there is a reduction in the margin of error. It would result to lesser possible values for the mean.

You might be interested in
Use the fundamental counting principle to determine the how many different outfits can be made from 4 pairs of jeans and 7 shirt
Mariana [72]

Answer:

28

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
1. The image below represents the dimensions of
andreyandreev [35.5K]

Answer:

V plus 5 is four

Step-by-step explanation:

dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load. dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load. dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load. dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load. dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load. dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load. dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load. dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load.

8 0
3 years ago
1. The mechanics at Lincoln Automotive are reborning a 6 in deep cylinder to fit a new piston. The machine they are using increa
Firdavs [7]

Answer:

0.0239\frac{in^{3}}{min}

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram of the cylinder. (See attached picture)

This diagram will help us visualize the problem better.

So we start by determining what data we already know:

Height=6in

Diameter=3.8in

Radius = 1.9 in (because the radius is half the length of the diameter)

The problem also states that the radius will increase on thousandth of an inch every 3 minutes. We can find the velocity at which the radius is increasing with this data:

r'=\frac{1/1000in}{3min}

which yields:

r'=\frac{1}{3000}\frac{in}{min}

with this information we can start solving the problem.

First, the problem wants us to know how fast the volume is increasing, so in order to find that we need to start with the volume formula for a cylinder, which is:

V=\pi r^{2}h

where V is the volumen, r is the radius, h is the height and π is a mathematical constant equal approximately to 3.1416.

Now, the height of the cylinder will not change at any time during the reborning, so we can directly substitute the provided height, so we get:

V=\pi r^{2}(6)

or

V=6 \pi r^{2}

We can now take the derivative to this formula so we get:

\frac{dV}{dt}=2(6)\pi r \frac{dr}{dt}

Which simplifies to:

\frac{dV}{dt}=12\pi r \frac{dr}{dt}

We can now substitute the data provided by the problem to get:

\frac{dV}{dt}=12\pi (1.9) (\frac{1}{3000})

which yields:

\frac{dV}{dt}=0.0239\frac{in^{3}}{min}

3 0
4 years ago
↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓<br> No Words <br> Part 1
MissTica
3m + 2n= p solve for n

subtract 3m on both sides
2n = p - 3m

divide both sides by 2
n = p/2 - 3m/2
-----------------------

xy - 5 = k solve for x
add 5 on both sides
xy = k + 5

divide both sides by y
x = k/y - 5/y
3 0
3 years ago
How to evaluate the limit
anzhelika [568]
\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}

Both the numerator and denominator are continuous at x=2, which means the quotient rule for limits applies:

\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2

Perhaps you meant to write that x\to-2 instead? In that case, you would have

\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5
4 0
3 years ago
Other questions:
  • I need help ASAP <br><br><br> -2x^2+x<br><br> 9-25x^2+8x<br><br> X^5+x^3-x^2-1
    6·1 answer
  • How to solve for angles of a triangle when I am given only sides
    11·1 answer
  • What is the domain of f(x)
    13·1 answer
  • Worth 40 points....answer is not 38
    8·2 answers
  • If a: b = 2:3, b: c = 4:3, and c: d = 7: 8, find a: d.
    14·1 answer
  • Which statement about the ordered pairs (2, −9)and (3, −6) is true for the equation 5x-y/3=13
    5·1 answer
  • What are two expressions that are equivalent to<br> -2(4-y)?
    11·1 answer
  • X/5+2 = -1<br> Solve 2-step equations
    6·2 answers
  • Plz HELPPP!!!
    6·1 answer
  • Which is the graph of y &lt;1 -3x?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!