What is the solution to the inequality? −4x−8>−20

NEED HELP ASAP

Alisiya [41]

Answer:

Divide, 16.

Step-by-step explanation:

So, lets look at the unit scale.

For every 16 ounces, there are 1 pound.

To convert ounces to pounds, the number must be divide by 16, since there are 16 ounces in one pound.

The first fill in box answer is division.

Next we must ifnd the actual amount of pounds.

We know that the box weights 96 ounces.

Now lets divide this by ounces per pound, and see what we get:

96/16

=

6

So the box weighs 6 pounds.

This is the answer to the second fill in question.

Hope this helps!

8 0

3 years ago

If B(x)=-1,then what is x

jekas [21]

Step-by-step explanation:

6 0

3 years ago

Question one please and show work

Ilya [14]

Answer:

Step-by-step explanation:

c is correct bcause if you work out a it says is less than. then the gcf is 2 and 3 but do 2 times 3

6 0

4 years ago

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A certain kind of sheet metal has, on average, 3 defects per 18 square feet. Assuming a Poisson distribution, find the probabili

Fofino [41]

Answer:

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have that:

3 defects per 18 square feet.

So for 31 square feet, we have to solve a rule of three

3 defects - 18 square feet

x defects - 31 square feet

$18x = 3*31$

$x = \frac{31*3}{18}$

$x = 5.17$

So $\mu = 5.17$

Assuming a Poisson distribution, find the probability that a 31 square foot metal sheet has at least 4 defects.

Either it has three or less defects, or it has at least 4 defects. The sum of the probabilities of these events is decimal 1.

So

$P(X \leq 3) + P(X \geq 4) = 1$

We want $P(X \geq 4)$

So

$P(X \geq 4) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.17}*(5.17)^{0}}{(0)!} = 0.0057$

$P(X = 1) = \frac{e^{-5.17}*(5.17)^{1}}{(1)!} = 0.0294$

$P(X = 2) = \frac{e^{-5.17}*(5.17)^{2}}{(2)!} = 0.0760$

$P(X = 3) = \frac{e^{-5.17}*(5.17)^{3}}{(3)!} = 0.1309$

So

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0057 + 0.0294 + 0.0760 + 0.1309 = 0.242$

Finally

$P(X \geq 4) = 1 - P(X \leq 3) = 1 - 0.242 = 0.758$

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

8 0

3 years ago

Orlando is doing a math problem where he needs to dilate a triangle by a scale factor of four. The ordered pairs for his pre-ima

Rainbow [258]

Dilation refers to a non rigid motion where a figure is transform and its image has the same form but a different size measure.
Dilation is define by the rule (x,y)-- (kx, ky) where k represents the scale factor.

On this exercise is given that a triangle with vertices (-2,1), (8,4), and (3,0) was dilated by a scale factor of four, and it is asked to find the vertices of the image of the triangle after the dilation occurred.

Pre-image Image
(-2,1) -- (-2*4,1*4) -- (-8,4)
(8,4) -- (8*4,4*4) -- (32,16)
(3,0) -- (3*4,0*4) -- (12,0)

The coordinates representing the vertices of the triangle's image are (-8,4), (32,16), and (12,0); meaning that the ordered pair which is not a coordinate for a point in the triangle's image is (2,1).

5 0

3 years ago

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