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SVETLANKA909090 [29]
3 years ago
10

Ammonia (NH3) clouds are present around some planets. Calculate the number of grams of ammonia produced by the reaction of 5.4 g

of hydrogen with an excess of nitrogen
N2 + 3 H2 -> 2 NH3
Chemistry
2 answers:
kenny6666 [7]3 years ago
7 0

30.6 g of ammonia are produced.

Answer:

given

mass of hydrogen =5.4 gram

mass of NH3=?

we have

3 moles of H2=2 moles of NH3

3×2g of H2=2×(14+3) g of NH3

6 g of H2=34 g of NH3

5.4 g of H2=34×5.4/6=30.6 g of NH3

Komok [63]3 years ago
5 0

Answer:

30.4 g. NH3

Explanation:

This problem tells us that the hydrogen (H2) is the limiting reactant, as there is "an excess of nitrogen." Using stoichiometry (the relationship between the various species of the equation), we can see that for every 3 moles of H2 consumed, 2 moles of NH3 are produced.

But before we can use that relationship to find the number of grams of ammonia produced, we need to convert the given grams of hydrogen into moles:

5.4 g x [1 mol H2/(1.008x2 g.)] = 2.67857 mol H2 (not using significant figures yet; want to be as accurate as possible)

Now, we can use the relationship between H2 and NH3.

2.67857 mol H2 x (2 mol NH3/3 mol H2) = 1.7857 mol NH3

Now, we have the number of moles of ammonia produced, but the answer asks us for grams. Use the molar mass of ammonia to convert.

1.7857 mol NH3 x 17.034 g. NH3/mol NH3 = 30.4 g. NH3 (used a default # of 3 sig figs)

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Answer:

Mole fraction Ar = 0.31

Explanation:

Remember that the sum of the mole fractions in a mixture of gases = 1

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4 0
3 years ago
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Answer:

ExpC

H

4

+  

2

O

2

 

→

 

C

O

2

+  

2

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2

O

This is the balanced reaction equation for the combustion of methane.

Explanation:

The Law of Conservation of Mass basically states that matter can neither be created nor destroyed. As such, we must be able to show this in our chemical reaction equations.

If you look at the equation above, you'll see an arrow that separates the reaction equation into two parts. This represents the direction of the reaction.

To the left of the arrow, we have our reactants.

To the right of the arrow, we have our products.

The quantity of each individual element in the left must equal the quantity of each individual element in the right.

So if you look below, you'll see the unbalanced equation, and I'll try to explain how to balance the reaction.

C

H

4

+  

O

2

 

→

 

C

O

2

+  

H

2

O

Our reactants in this equation are  

C

H

4

and  

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2

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Our next step is to break these down into individual atoms.

We have:

1 C atom, 4 H atoms & 2 O atoms.

If you're confused by this, look to see the little number to the bottom right of each element, the subscript, and it tells you how many of each atom are in the molecule. Make sense?

Now we look to the other side of the equation.

Here we see our products are  

C

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2

+  

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2

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Again, we break these down into individual atoms again.

We have:

1 C atom, 2 H atom, 3 O atom

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