Answer:
see below
Explanation:
a. 0.1886 x 12
=2.2632
This has 2 sig figures so the answer can only have 2 sig figures
2.3
b. 2.995 - 0.16685
=2.82815
The most accurate in the problem is to thousands place so our answer can only be accurate to the thousands place
2.828
c. 910 x 0.18945=172.3995
The least number of significant figures is 3 so the answer can only have 3 significant figures
172
From the information given, cannon ball weighs 40 kg and has a potential energy of 14000 J.
We need to find its height.
We will use the formula P.E = mgh
Therefore h = P.E / mg
where P.E is the potential energy,
m is mass in kg,
g is acceleration due to gravity (9.8 m/s²)
h is the height of the object's displacement in meters.
h = P.E. / mg
h = 14000 / 40 × 9.8
h = 14000 / 392
h = 35.7
Therefore the canon ball was 35.7 meters high.
<h2>
Answer: On December 20th, 1951 in Idaho, United States.
</h2>
The world's first experimental nuclear power plant was the Experimental Breeder Reactor Number One (EBR-I), which was built in a desert in Idaho, United States.
This reactor made history when, on December 20th, 1951, four 200-watt light bulbs were illuminated by means of atomic energy, specifically by nuclear fission reaction.
Ok I don’t know the answer I’m in 5th grade but 2431 is wrong
