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White raven [17]
3 years ago
14

Which situations describe an elastic collision?

Physics
2 answers:
Charra [1.4K]3 years ago
4 0

Answer;

A. two glass marbles bounce off each other.

Explanation;

Elastic collisions are collisions in which both momentum and kinetic energy are conserved. The total system kinetic energy before the collision equals the total system kinetic energy after the collision. If total kinetic energy is not conserved, then the collision is referred to as an inelastic collision.

An elastic collision occurs when the two objects "bounce" apart when they collide. Two rubber balls are a good example. In an elastic collision, both momentum and kinetic energy are conserved. Almost no energy is lost to sound, heat, or deformation.

Elan Coil [88]3 years ago
3 0
Elastic collisions<span> are </span>collisions<span> in which both momentum and kinetic energy are conserved. I think the correct answer from the choices listed above is option A. Two </span><span>glass marbles bounce off each other is an example of an elastic collision. Hope this answers the question.</span>
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The passenger-side rear view mirror on a car says, “Objects in the mirror may be closer than they appear”. Assuming the images a
Ipatiy [6.2K]

Answer:

the mirror is a convex mirror

4 0
3 years ago
Pc13 is a compound used to make pesticides. A reaction requires that 96.7 kg of pc13 be raised from 31.7 degrees celcius to 69.2
siniylev [52]

Answer:

Energy required = 3169.34 Joules.

Explanation:

The quantity of energy (Q) required can be determined by;

Q = mcΔθ

Where: m is the mass, c is the specific heat and Δθ is the change in temperature.

But, m = 96.7 kg, c = 0.874 J/(kg^{o} C), T_{2} = 69.2^{o} and T_{1} = 31.7^{o}.

So that,

Q = mc(T_{2} - T_{1})

   = 96.7 x 0.874 x (69.2^{o} - 31.7^{o})

  = 96.7 x 0.874 x 37.5

  = 3169.3425

Q = 3169.34

   = 3.2 KJ

The amount of energy required is 3169.34 Joules.

8 0
3 years ago
A certain kind of glass has an index of refraction of 1.640 for blue light of wavelength 440 nm and an index of 1.595 for red li
seraphim [82]

Answer: 18.27°

Explanation:

Given

Index of refraction of blue light, n(b) = 1.64

Wavelength of blue light, λ(b) = 440 nm

Index of refraction of red light, n(r) = 1.595

Wavelength of red light, λ(r) = 670 nm

Angle of incident, θ = 30°

Angle of refraction of red light is

θ(r) = sin^-1 [(n(a)* sin θ) / n(r)], where n(a) = index of refraction of air = 1

So that,

θ(r) = sin^-1 [(1 * sin 30) / 1.595]

θ(r) = sin^-1 (0.5 / 1.595)

θ(r) = sin^-1 0.3135

θ(r) = 18.27°

4 0
3 years ago
Calculate the potential energy of a 4 kg cat crouched 3 meters off the ground
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Ep = (4)(9.81)(3)

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= 1.2x10^2 Joules
7 0
3 years ago
Read 2 more answers
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Sedaia [141]

The driver is tooling along in his snowmobile, pointed north,
at 8.5 m/s.

He's carrying the flares with him, so the flares are also moving north
at 8.5 m/s.

When he fires the flare straight up, it has a vertical velocity of 4.3 m/s
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The magnitude of the net velocity is √(4.3² + 8.5²) .
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The angle above horizontal is the angle that has a tangent of  4.3/8.5 .
I'll let you work out the angle.
 
8 0
3 years ago
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