Answer:
The age of the ore is 4.796*10^9 years.
Explanation:
To solve this question, we use the formula;
A(t) =A(o)(1/2)^t/t1/2
where;
A(t) =3.22mg
A(o) = 6.731mg
t1/2 = 4.51*70^9 years
t = age of the ore
So,
A(t) =A(o)(1/2)^t/t1/2
3.22 = 6.73 (1/2)^t/4.51*10^9
Divide both sides by 6.73
3.22/6.73= (1/2)^t/4.51*10^9
0.47825= (0.5)^t/4.51*10^9
Log 0.4785 = t/4.51*10^9 • log 0.5
Log 0.4785/log 0.5 • 4.51*10^9 = t
t = 1.0634 * 4.51*10^9
t = 4.796*10^9
So therefore, the age of the ore is approximately 4.796*10^9 years.
