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bekas [8.4K]
3 years ago
6

What causes a water strider to be able to walk on water?

Chemistry
2 answers:
Lena [83]3 years ago
8 0

Answer:

By repelling water, the tiny water striders stand on the water's surface and the captured airs allows them to float and move easily.  so number 2. Surface Tension.

Explanation:

The attraction between water molecules creates tension and a very delicate membrane. Water striders walk on this membrane. ... The legs have tiny hairs that repel water and capture air.

Nina [5.8K]3 years ago
4 0

Answer:

Water striders use the high surface tension of water and long, hydrophobic legs to help them stay above water.

Hope this helps! (:

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Which pair of elements would you expect to exhibit the greatest similarity in their physical and chemical properties? Sr, Te Ga,
Anvisha [2.4K]

Answer:

Explanation:

N and P will have similarity

Electronic configuration of N

2,5

1s²2s²p⁵

Electronic configuration of  P

1s²2s²2p⁶3s²3p⁵

Electronic configuration bears similarity.

Both have 5 electrons in their outermost orbits . So they exhibit similarity in their properties. Both belong to the same 15 th group of periodic table.

Sr and Rb too bear much similarity . Both are strongly electro-positive metal , difference in their atomic no being only one.

5 0
3 years ago
An ionic compound is
Musya8 [376]

Answer:

a compound

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7 0
3 years ago
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PLZ HELP PLZ SOMEONE PLZ How old do u need to work as a secret agent
zmey [24]

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3 0
3 years ago
Please help me out asap. I’ll give brainliest
mestny [16]

Answer:

I belive the answer is A but the image quality is hard to tell.

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As pressure increases the higher the melting point of rock becomes making it harder to melt, thats why molten rocks brought to the surface melt because of the change in pressure.  

7 0
2 years ago
How long does it take for a 12.62g sample of ammonia to heat from 209K to 367K if heated at a constant rate of 6.0kj/min? The me
Georgia [21]
First, consider the steps to heat the sample from 209 K to 367K.

1) Heating in liquid state from 209 K to 239.82 K

2) Vaporaizing at 239.82 K

3) Heating in gaseous state from 239.82 K to 367 K.


Second, calculate the amount of heat required for each step.

1) Liquid heating

Ammonia = NH3 => molar mass = 14.0 g/mol + 3*1g/mol = 17g/mol

=> number of moles = 12.62 g / 17 g/mol = 0.742 mol

Heat1 = #moles * heat capacity * ΔT

Heat1 = 0.742 mol * 80.8 J/mol*K * (239.82K - 209K) = 1,847.77 J

2) Vaporization

Heat2 = # moles * H vap

Heat2 = 0.742 mol * 23.33 kJ/mol = 17.31 kJ = 17310 J

3) Vapor heating

Heat3 = #moles * heat capacity * ΔT

Heat3 = 0.742 mol * 35.06 J / (mol*K) * (367K - 239.82K) = 3,308.53 J

Third, add up the heats for every steps:

Total heat = 1,847.77 J + 17,310 J + 3,308.53 J = 22,466.3 J

Fourth, divide the total heat by the heat rate:

Time = 22,466.3 J / (6000.0 J/min) = 3.7 min

Answer: 3.7 min


3 0
3 years ago
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