A student pushes on a crate with a force of 100 Newtons directed to the right.
1 answer:
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<u>Answer:</u>
The velocity of the truck is 34 m/s.
<u>Explanation:</u>
The momentum (p) of an object is the product of its mass (m) and its velocity (v) which can be written as:
<em>p = mv</em>
Here in this problem, we are given a truck which has a momentum of 40120 kg and a mass of 1180 kg and we are to find its velocity.
So substituting the given values in the above formula to find the velocity of the truck.
Truck's velocity = = 34 m/s.
<u>Answer:</u>
C = 0.025F
<u>Explanation:</u>
Charge =q=3×C
Voltage=V=120V
Q=CV
C=Q/V
=3×/120
=1/40×
C = 0.025F
C=2.5 C 0r 25 ×
F
θ = angle of the incline surface from the horizontal surface = 25⁰
μ = Coefficient of friction = 0.15
m = mass of the person = 65 kg
= kinetic frictional force acting on the person as he slides down
mg = weight of the person acting in down direction
= normal force by the incline surface on the person
the free body diagram showing the forces acting on the person is given as
