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larisa [96]
3 years ago
10

Jason knows that the equation to calculate the period of a simple pendium T=2π√L/8, where T is the period, L is the length of th

e rod and g is the acceleration due to gravity. He who knows that the frequency (f) of the pendulum is the reciprocal of period. How can he express L in terms of g and f?
t =2\pi\sqrt{ \frac{l}{8} }
​

Physics
1 answer:
erik [133]3 years ago
3 0

Answer: L can be expressed in terms of g and f as

L = g/(2πf)^2

Explanation: Please see the attachments below

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d

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2 years ago
Two point charges are 10.0cm apart and have charges of 2.0uC and -2.0uC, respectively. What is the magnitude of the electric fie
elena-14-01-66 [18.8K]
The electric field generated by a point charge is given by:
E= k_e \frac{Q}{r^2}
where
k_e = 8.99 \cdot 10^9 Nm^2 C^{-2} is the Coulomb's constant
Q is the charge
r is the distance from the charge

We want to know the net electric field at the midpoint between the two charges, so at a distance of r=5.0 cm=0.05 m from each of them. 

Let's calculate first the electric field generated by the positive charge at that point:
E_1=k_e  \frac{Q_1}{r^2}=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(2.0 \cdot 10^{-6} C)}{(0.05 m)^2} =+7.19 \cdot 10^6 N/C
where the positive sign means its direction is away from the charge.

while the electric field generated by the negative charge is:
E_2=k_e \frac{Q_1}{r^2}=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(-2.0 \cdot 10^{-6} C)}{(0.05 m)^2} =-7.19 \cdot 10^6 N/C
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If we assume that the positive charge is on the left and the negative charge is on the right, we see that E1 is directed to the right, and E2 is directed to the right as well. This means that the net electric field at the midpoint between the two charges is just the sum of the two fields:
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3 years ago
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For further reference:

brainly.com/question/24478168?referrer=searchResults

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3 0
1 year ago
A vertical spring stretches 9.6 cm when a 1.3 kg block is hung from its end. (a) Calculate the spring constant. This block is th
tatiyna

Answer:

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Explanation:

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