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Viefleur [7K]
4 years ago
6

Two students are sitting 1.50 m apart. One student has a mass of 70.0 kg and the other has a mass of 52.0 kg. What is the gravit

ational force between them?
Physics
1 answer:
algol [13]4 years ago
5 0

Answer:

The gravitational force between them is 1.079\times10^{-7}\ N.

Explanation:

Given that,

Distance = 1.50 m

Mass of one student = 70.0 kg

Mass of other student = 52.0 kg

We need to calculate the gravitational force

Using formula of gravitational force

F=\dfrac{Gm_{1}m_{2}}{r^2}

Where, m₁ = mass of one student

m₂ = mass of other studen

r = distance between them

Put the value into the formula

F=\dfrac{6.67\times10^{-11}\times70.0\times52.0}{1.50^2}

F=1.079\times10^{-7}\ N

Hence, The gravitational force between them is 1.079\times10^{-7}\ N.

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A 15-kg block at rest on a horizontal frictionless surface is attached to a very light ideal spring of force constant 450 N/m. T
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Answer:

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Find the equivalent resistance, current, and voltage across each resistor when the specified resistors are connected across a 20
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Answer:

Explanation:

The question is incomplete. Here is the complete question.

"Find the equivalent resistance, the current supplied by the battery and the current through each resistor when the specified resistors are connected across a 20-V battery. Part (a) uses two resistors with resistance values that can be set with the animation sliders, and you can use the animation to verify your calculation. In part (b), three resistors are specified. (a) Two resistors are connected in series across a 20-V battery. Let R1 = 1 Ω and R2 = 2 Ω. Rea = (b) Add a third resistor to the circuit in series. Let R1 = 1 Ω, R2 = 2 Ω, and R3 = 3 Ω"

Using ohms law formula to solve the problem

E = IRt

E is the supply voltage

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a) Given two resistances

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= 1ohms + 2ohms

= 3ohms

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Using the formula E = IRt

I = E/Rt

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The current in both resistors is 6.67A

- Different voltage flows across a series connected circuit.

Using the formula V = IR

V is the voltage across each resistor

I is the current in each resistor

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V = 6.67×1

V = 6.67Volts

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V = 6.67×2

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b) If the resistors are three

R1 = 1ohms, R2 = 2ohms R3 = 3ohms

- Total equivalent resistance = 1+2+3

= 6ohms

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I = 20/6

I = 3.33A

Since the same current flows through the resistors, the current across each of them is 3.33A

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V = IR

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V = 3.33×1

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For 2ohms resistor

V = 3.33×2

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For 3ohms resistor

V = 3.33×3

V = 9.99volts

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