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Komok [63]
3 years ago
8

PLEASE HELP ASAP!!!

Physics
1 answer:
Mama L [17]3 years ago
8 0
C landslide I believe
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Piston 1 in the figure has a diameter of 1.87 cm.
melisa1 [442]

The force F, necessary to support an object with a mass of 991 kg placed on piston 2 is 373.8 N.

<h3>What is the force required to support the weight on piston 2?</h3>

The  force, F required to support the weight on piston 2 is calculated as follows:

  • F = F₂ * A₁/A₂

f = 991 * 9.81 = 9721.71 N

A₂ = (9.46/2)² = 22.373

A₁ =  (1.87/2)² = 0.874

F = 9721.71 * 0.874/22.373

F = 373.8 N

Inc conclusion, a smaller force is applied to lift the larger force at Piston 2.

Learn more about force and area at: brainly.com/question/14874331
#SPJ1

7 0
2 years ago
The electric potential is 40 V at point A near a uniformly charged sphere. At point B, 2.0 μm farther away from the sphere, the
KatRina [158]

Answer:

Explanation:

Potential at a point near a charge = Q / 4πε₀ R

where Q is charge given , R is distance of point from the charge .

Q / 4πε₀ R  = 40

Electric field E at A = -dV / dR

= .16 x 10⁻³ / 2 x 10⁻⁶

= .08 x 10³

= 80 N/C

E = Q / 4πε₀ R²

80 =  Q / 4πε₀ R x R

80 = 40 / R

R = 40 / 80

= .5 m .

4 0
3 years ago
An explanation can be consistent but may not be the best explanation for a phenomenon
notka56 [123]

Answer:

true

Explanation:

8 0
3 years ago
Read 2 more answers
A 3rd harmonic is being produced in a tube that is open at both ends. The tube is 3 meters long and
attashe74 [19]

The frequency of the second harmonic is 880 Hz (a pitch of A5). The speed of sound through the pipe is 350 m/sec. Find the frequency of the first harmonic and the length of the pipe. The length of an air column is related mathematically to the wavelength of the wave which resonates within it.

4 0
3 years ago
Which is true about total internal reflection?
Shkiper50 [21]

Answer:

It can occur only when light is incident on an interface where the index of refraction on the other side is less.

Explanation:

When the light passes from a denser medium, with refractive index n1, to another less dense medium, with refractive index n2, the incident light beam is refracted in such a way that it is not able to cross the surface between both media, the light beam is fully reflected and completely confining in the optically denser medium through which it propagates. For this phenomenon to occur, it is necessary that the angle of the incident light beam with respect to the normal be greater than or equal to the critical incidence angle θc. The critical angle can be calculated as :

\theta_c=arcsin(\frac{n_2}{n_1})

7 0
3 years ago
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