Imagine another solar system, with a star of the same mass as the Sun. Suppose a planet with a mass twice that of Earth (2 Earth
1 answer:
Answer:
Time period, T = 403.78 years
Explanation:
It is given that,
Orbital distance,
Mass of the Earth,
Mass of the planet,
Let T is the orbital period of this planet. The Kepler's third law of motion gives the relation between the orbital period and the orbital distance.
or
T = 403.78 years
So, the orbital period of this planet is 404 years. Hence, this is the required solution.
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