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kolezko [41]
3 years ago
12

Compare and contrast the geocentric view of the solar system with the heliocentric view of the solar system

Physics
1 answer:
Mandarinka [93]3 years ago
7 0
This is fairly easy. The earlier view of the solar system (geocentric) was all based on how other planets and the sun were constantly revolving the earth and we were completely stationary. The Heliocentric view has been proved to be accurate, and it is that the sun is stationary and the planets are revolving it. The similarities are that in that time, it was a continued belief that the planets were the Roman Gods, i.e. Jupiter, Neptune. Another thing is that they were correct in the Geocentric theory with the thought that the planets revolved around something.
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I need help finding the answer
miss Akunina [59]

Speed = (distance) / (time)

Speed = (2.3 m) / (3 sec)

Speed = (2.3/3) (m/s)

<em>Speed = 0.766... m/s</em>

5 0
3 years ago
.A hard rubber ball, released at chest height, falls to the pavement and bounces back to nearly the same height. When it is in c
ohaa [14]

Answer:

 a = 1.1 10⁵ m / s²

Explanation:

This is a momentum exercise, where we use the relationship between momentum and momentum

          I = ∫ F dt = Δp

= p_f - p₀

as they indicate that the ball bounces at the same height, we can assume that the moment when it reaches the ground is equal to the moment when it bounces, but in the opposite direction

        F t = 2 (m v)

therefore the average force is

         F = 2 m v / t

where in general the mass of the ball unknown, the velocity of the ball can be calculated using the conservation of energy

starting point. Done the ball is released with zero initial velocity

        Em₀ = U = mgh

final point. Upon reaching the ground, just before the deformation begins

        Em_f = K = ½ m v²

energy is conserved in this system

        Em₀ = Em_f

        m g h = ½ m v²

        v = √ (2gh)

This is the velocity of the body when it reaches the ground, so the force remains

        F = 2m √(2gh)   /t

where the height of the person's chest is known and the time that the impact with the floor lasts must be estimated in general is of the order of milli seconds

knowing this force let's use Newton's second law

          F = m a

          a = F / m

 

          a = 2 √(2gh) / t

We can estimate the order of magnitude of this acceleration, assuming the person's chest height of h = 1.5 m and a collision time of t = 1 10⁻³ s

         a = 2 √ (2 9.8 1.5) / 10⁻³

         a = 1.1 10⁵ m / s²

6 0
2 years ago
Which of these is NOT a possible type of energy transformation?
Orlov [11]

to be franc i really think the answer is B

6 0
3 years ago
According to meet one law of universal gravitation, gravity increases when?​
mina [271]

Newton's law of universal gravitation states that every point mass in the universe attracts every other point mass with a force that is directly proportional to the product of their masses, and inversely proportional to the square of the distance between them. Newton's law of universal gravitation states that every point mass in the universe attracts every other point mass with a force that is directly proportional to the product of their masses, and inversely proportional to the square of the distance between them.

5 0
2 years ago
A 2.50 kg ball moving at 7.50 m/s is caught by a 70.0 kg man while the man is standing on ice. What is the common velocity of th
yarga [219]

Answer:

V = 2.5*7.0 / ( 2.5 + 70 )

8 0
2 years ago
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