Answer:
The base and height of the garden are 4.60 ft and 5.60 ft.
Step-by-step explanation:
The area of the garden is, <em>A</em> = 24 ft².
The base height of the garden are:
base (<em>b</em>) = 6x - 4
height (<em>h</em>) = x + 3
Compute the value of <em>x</em> as follows:

The last equation is a quadratic equation.
Compute the roots of the quadratic equation as follows:

The value of base and height are:

Thus, the base and height of the garden are 4.60 ft and 5.60 ft.
2 kg. Each liter is equal to 1 kg
Remark
A cube has six sides, all of them equal. The formula for 1 side is s^2. The formula for all six = 6s^2.
Step One
Find the surface area of the larger cube.
Area = 6 *s^2
s = 15
Area = 6 *15^2
Area = 6 * 225
Area = 1350
Step Two
Find the area of the smaller cube
Area = 6s^2
Area = 6 * 12^2
Area = 6 * 144
Area = 864
Step Three
Find the difference
Area1 - Area2 = difference
1350 - 864 = 486
The difference is area = 486 units^2 <<<<< Answer
There is a slightly shorter way. Take out the common factor of 6
Difference = 6 * (15^2 - 12^2)
Difference = 6 * (225 - 144)
Difference = 6 * (81)
Difference = 486
The roots of an equation are simply the x-intercepts of the equation.
See below for the proof that
has at least two real roots
The equation is given as: 
There are several ways to show that an equation has real roots, one of these ways is by using graphs.
See attachment for the graph of 
Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)
From the attached graph, we can see that
crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500
This means that
has at least two real roots
Read more about roots of an equation at:
brainly.com/question/12912962
Answer:
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Step-by-step explanation: