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3 years ago

A scientist wants to measure the relationship between humidity in the

Physics

1 answer:

ICE Princess25 [194]3 years ago

7 0

Answer:

Explanation:

The most suitable testable question. in this case, would be that 'are there more home runs during the more humid months of the summer?'

Since the aim of the investigation is to find the relationship between humidity and the number of home runs, measuring the number of home runs during the more humid months in the summer and comparing the data to the number of home runs during the less humid months in the same summer would provide the answer.

Only option D raises a valid question that is relevant to the aim of the investigation.

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¿ qué es un motor de explosión?

ArbitrLikvidat [17]

Answer:

es un motor de combustión interna con encendido por chispa.

5 0

3 years ago

While driving, your car has an initial position of 3.2 m, an initial velocity of -8.4 m/s, and

KIM [24]

Answer:

The position of the car at t = 1.5 s is at -8.1625 meters

Explanation:

The initial position of the car is 3.2 meters

The initial velocity is -8.4 m/s

The constant acceleration is 1.1 m/s²

We need to find the final position of the car at the time t = 1.5 seconds

The displacement s = final position - initial position

$s=ut+\frac{1}{2}at^{2}$ , where u is the initial velocity, a is the

constant acceleration and t is the time

So we can find the final velocity by using the rule:

final position - initial position = $ut+\frac{1}{2}at^{2}$

initial position = 3.2 meters , u = -8.4 m/s , a = 1.1 ²m/s , t = 1.5 s

Substitute these values in the rule

final position - 3.2 = $(-8.4)(1.5)+\frac{1}{2}(1.1)(1.5)^{2}$

final position - 3.2 = -12.6 + 1.2375

final position - 3.2 = -11.3625

add 3.2 for both sides

final position = -8.1625

That means the car is at 8.1625 meters in opposite direction

The position of the car at t = 1.5 s is at -8.1625 meters

4 0

3 years ago

A cheetah can run at a maximum speed 97.8 km/h and a gazelle can run at a maximum speed of 78.2 km/h. If both animals are runnin

emmainna [20.7K]

(1)

Cheetah speed: $v_c = 97.8 km/h=27.2 m/s$

Its position at time t is given by

$S_c (t)= v_c t$ (1)

Gazelle speed: $v_g = 78.2 km/h=21.7 m/s$

the gazelle starts S0=96.8 m ahead, therefore its position at time t is given by

$S_g(t)=S_0 +v_g t$ (2)

The cheetah reaches the gazelle when $S_c=S_g$ . Therefore, equalizing (1) and (2) and solving for t, we find the time the cheetah needs to catch the gazelle: