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2 years ago

Whats the difference between kinetic and potential energy?

Physics

1 answer:

damaskus [11]2 years ago

5 0

Kinetic energy is energy in motion and potential energy is stored energy

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Hey help me plzzzzz i will mark brainliest

vodomira [7]

Answer:

The answer to your question is given below.

Explanation:

Mechanical advantage (MA) = Load (L)/Effort (E)

MA = L/E

Velocity ratio (VR) = Distance moved by load (l) / Distance moved by effort (e)

VR = l/e

Efficiency = work done by machine (Wd) /work put into the machine (Wp) x 100

Efficiency = Wd/Wp x100

Recall:

Work = Force x distance

Therefore,

Work done by machine (wd) = load (L) x distance (l)

Wd = L x l

Work put into the machine (Wp) = effort (E) x distance (e)

Wp = E x e

Note: the load and effort are measured in Newton (N), while the distance is measured in metre (m)

Efficiency = Wd/Wp x100

Efficiency = (L x l) / (E x e) x 100

Rearrange

Efficiency = L/E ÷ l/e x 100

But:

MA = L/E

VR = l/e

Therefore,

Efficiency = L/E ÷ l/e x 100

Efficiency = MA ÷ VR x 100

Efficiency = MA / VR x 100

7 0

2 years ago

Voltage drop is a better measurement of resistance than testing static resistance because ________.

gavmur [86]

Voltage drop is a better measurement of resistance than testing static resistance because: current flow creates heat which adds to circuit resistance

The current flow or electric current is the measure of the electrons flow around a circuit. It is measured in amperes or "amps". If the current is higher the electrons flow is greater.

<h3>What is electricity?</h3>

Electricity or electrical energy is the energy that occurs due to the movement of electrons in the materials that are considered conductors.

Learn more about electricity at: brainly.com/question/23063355

#SPJ4

7 0

1 year ago

Find electric field at point p which is a distance l away from the both +q and -q

denis-greek [22]

Answer:

$\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }$

Explanation:

As given point p is equidistant from both the charges

It must be in the middle of both the charges

Assuming all 3 points lie on the same line

Electric Field due a charge q at a point ,distance r away

$=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{r^{2} }$

Where

q is the charge
r is the distance
$E$ is the permittivity of medium

Let electric field due to charge q be F1 and -q be F2

I is the distance of P from q and also from charge -q

⇒

F1 $=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }$

F2 $=\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }$

⇒

F1+F2= $\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }$

8 0

2 years ago

Raw data often appears in published scientific journals. Please select the best answer from the choices provided T F

Hatshy [7]

This statement is false

5 0

2 years ago

Read 2 more answers

Can a falling object reach terminal velocity in outer space? Explain.

Damm [24]

Ith air resistance acting on an object that has been dropped, the object will eventually reach a terminal velocity, which is around 53 m/s (195 km/h or 122 mph) for a human skydiver. ... (On the Moon, the gravitational acceleration is much less than on Earth, approximately 1.6 m/s2.)

6 0

2 years ago