How can rice and flour mixture could be separated?

What volume does 4.24g of argon gas occupy at 58.2 degrees celcuis and 1528torr

lilavasa [31]

Answer:

V = 1.434 L

Explanation:

Given data:

Mass of argon = 4.24 g

Temperature = 58.2 °C

Pressure = 1528 torr

Volume = ?

Solution:

58.2 °C = 58.2 + 273 = 331.2 K

1528/760= 2.01 atm

Number of moles:

Number of moles = mass/molar mass

Number of moles = 4.24 g / 39.948 g/mol

Number of moles = 0.106 mol

Volume:

PV = nRT

V = nRT/P

V = 0.106 mol ×0.0821. atm. L. mol⁻¹. K⁻¹ × 331.2K/ 2.01 atm

V = 2.88 atm L/ 2.01 atm

V = 1.434 L

6 0

3 years ago

The expression of the theoretical yield (TY) in function of limiting reagent (LR) of a reaction is as follows: TY = ideal mole r

spin [16.1K]

Answer: The theoretical yield of acetanilide is 6.5 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For aniline:

Given mass of aniline = $4.50\times 10^0=4.50g$ (We know that: $10^0=1$ )

Molar mass of aniline = 93.13 g/mol

Putting values in equation 1, we get:

$\text{Moles of aniline}=\frac{4.50g}{93.13g/mol}=0.048mol$

For acetic anhydride:

To calculate the mass of acetic anhydride, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Volume of acetic anhydride = $(1.25\times \text{Mass of aniline})=1.25\times 4.50=5.625mL$

Density of acetic anhydride = 1.08 g/mL

Putting values in above equation:

$1.08g/mL=\frac{\text{Mass of acetic anhydride}}{5.625mL}\\\\\text{Mass of acetic anhydride}=(1.08g/mL\times 5.625mL)=6.08g$

Given mass of acetic anhydride = 6.08 g

Molar mass of acetic anhydride = 102.1 g/mol

Putting values in equation 1, we get:

$\text{Moles of acetic anhydride}=\frac{6.08g}{102.1g/mol}=0.06mol$

The chemical equation for the reaction of aniline and acetic anhydride follows:

$C_6H_5NH_2+CH_3COOCOCH_3\rightarrow C_6H_5NHCOCH_3+CH_3COOH$

By Stoichiometry of the reaction:

1 mole of aniline reacts with 1 mole of acetic anhydride

So, 0.048 moles of aniline will react with = $\frac{1}{1}\times 0.048=0.048mol$ of acetic anhydride

As, given amount of acetic anhydride is more than the required amount. So, it is considered as an excess reagent.

Thus, aniline is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of aniline produces 1 mole of acetanilide

So, 0.048 moles of aniline will produce = $\frac{1}{1}\times 0.048=0.048mol$ of acetanilide

Now, calculating the theoretical yield of acetanilide by using equation 1:

Moles of acetanilide = 0.048 moles

Molar mass of acetanilide = 135.17 g/mol

Putting values in equation 1, we get:

$0.048mol=\frac{\text{Mass of acetanilide}}{135.17g/mol}\\\\\text{Mass of acetanilide}=(0.048mol\times 135.17g/mol)=6.5g$

Hence, the theoretical yield of acetanilide is 6.5 grams.

3 0

4 years ago

What dose the saying Stars must die for others to be born mean

Orlov [11]

Answer:

-> there isnt an exact answer

Explanation:

stars have a cycle of life, like humans and other organisms. when they are dying they may get hotter or bigger. they will become red giants, and may explode.. kinds like the big bang theory. it will leave a small white dwarf star behind, about the size of earth, and it is super hot. the stars contain dark matter which will be spewed into the galaxy planting a path for future stars

I reccomend searching google for an exact answer

3 0

3 years ago

For each of the following cases, identify the order with respect to the reactant, A. Case (A ----> product)

damaskus [11]

Answer:

The answers to the question are

1. 2nd and above order order

2. 2nd order

3. 1/2 order

4. 1st order

5. 0 order

Explanation:

We have $\frac{N}{N_{0} } = e^{-\lambda t}$

1. For nth order reaction half life $t_{\frac{1}{2} }$ ∝ $\frac{1}{[A_{0} ]^{n-1} }$

Therefore for a 0 order reaction increasing concentration of the reactant there will increase $t_{\frac{1}{2} }$

First order reaction is independent [A₀].

Second order reaction [A₀] decrease, increase.

Similarly for a third order reaction

1. 2nd order

2. 2nd order reaction

3. Order of reaction is 1/2.

4. 1st order reaction.

5. Zero order reaction.

5 0

3 years ago

In which pair do both compounds exhibit predominantly ionic bonding? A) KCl and CO2 B) SO2 and BaF2 C) F2 and N2O D) N2O3 and Rb

gtnhenbr [62]

Answer:

E) NaF and SrO

Explanation:

The ionic bonding occurs between atoms with a great difference in electronegativity. This usually happens between a metal and a non-metal.

In which pair do both compounds exhibit predominantly ionic bonding?

A) KCl and CO₂. NO. C and O are non-metals and present covalent bonding.

B) SO₂ and BaF₂. NO. S and O are non-metals and present covalent bonding.

C) F₂ and N₂O. NO. Both compounds contain non-metals and present covalent bonding.

D) N₂O₃ and Rb₂O. NO. N and O are non-metals and present covalent bonding.

E) NaF and SrO. YES. Na and Sr are metals while F and O are non-metals.

5 0

3 years ago