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The question is incomplete, the complete question is;
Enter the chemical formula of a binary molecular compound of hydrogen and a Group 6A element that can reasonably be expected to be more acidic in aqueous solution than H2S , e.g. have a larger Ka.
Answer:
H2Se
Explanation:
The acidity and extent of acid dissociation (shown by Ka value) depends on the nature of the bond between hydrogen and the group 6A element.
If we compare the H-S bond and the H-Se bond, we will discover that the H-Se bond is longer, weaker and breaks more easily than the H-S bond. As a result of this, H2Se is more acidic than H2S.
<span>Answer: 0.00 meters
Solution:
Step 1: Define displacement
DISPLACEMENT = a vector quantity that describes "linear or angular distance in a given direction between a body or point and a reference position."
Step 2: Understand the question
Assumption 1: Assume that when the ant moves 4.25 meters from its origin to its nest, it is moving in a positive direction (on a graph you would draw a line along the x-axis from its origin to +4.25).
Assumption 2: Assume that when the ant "turns around...back to the source of food", it is moving back in the negative direction (towards the origin).
Step 3: Analyze the question
What is the distance between where the ant originally started and where it ended its journey?
The ant started and ended its journey in the same place.
While it traveled a distance of 8.52 meters (2 * 4.26 = 8.52), it's displacement is actually 0.00 meters (4.26 + (-4.26) = 0.00)
Therefore, the answer is 0.00 meters</span>
The logarithmic of the reciprocal of hydrogen - ion concentrate in grams atoms per litre
