Answer:
Explanation:
distance travelled s = 10 cm
speed v = 1.4 x 10⁶ m /s
v² = u² + 2as
u = 0
v² = 2as
( 1.4 x 10⁶ )² = 2 x a x .10
a = 9.8 x 10¹² m /s²
force on proton = mass x acceleration
= 1.67 x 10⁻²⁷ x 9.8 x 10¹²
= 16.366 x 10⁻¹⁵ N .
If magnitude of electric field be E
force on proton
= E x charge on proton
= E x 1.6 x 10⁻¹⁹
E x 1.6 x 10⁻¹⁹ = 16.366 x 10⁻¹⁵
E = 10.22 x 10⁴ N/C
The direction of electric field will be positive x - direction .
b )
Speed of proton = 1.4 x 10⁶ m /s .
