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Alina [70]
3 years ago
13

A proton is released from rest in a uniform electric field. After the proton has traveled a distance of 10.0 cm, its speed is 1.

4 x 10^6 m/s in the positive x direction.
Required:
a. Find the magnitude and direction of the electric field.
b. Find the speed of the proton
Physics
1 answer:
GREYUIT [131]3 years ago
6 0

Answer:

Explanation:

distance travelled s = 10 cm

speed v = 1.4 x 10⁶ m /s

v² = u² + 2as

u = 0

v² = 2as

( 1.4 x 10⁶ )² = 2 x a x .10

a = 9.8 x 10¹² m /s²

force on proton = mass x acceleration

= 1.67 x 10⁻²⁷ x 9.8 x 10¹²

= 16.366 x 10⁻¹⁵ N .

If magnitude of electric field be E

force on proton

= E x charge on proton

= E x 1.6 x 10⁻¹⁹

E x 1.6 x 10⁻¹⁹ = 16.366 x 10⁻¹⁵

E = 10.22 x 10⁴ N/C

The direction of electric field will be positive x - direction .

b )

Speed of proton = 1.4 x 10⁶  m /s .

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Which is an IUPAC name for a covalent compound
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2 years ago
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A woman walked 115 m. As she did so, her speed increased from 4.20 m/s to 5.00 m/s. How long did it take her to walk this distan
ASHA 777 [7]

Answer:

25 seconds

Explanation:

Assuming the woman is accelerating at a constant rate of a \;\;m/s^2 from the initial velocity, u=4.20 m/s, to the final velocity, v=5.00 m/s.

Let she takes t seconds to cover the distance, s=115 m.

As acceleration, a=\frac{v-u}{t}=\frac{5-4.2}{t}

\Rightarrow at=0.8\cdots(i)

Now, from the equation of motion

s=ut+\frac 12 at^2

\Rightarrow s=ut+\frac 12 at(t)

\Rightarrow 115=4.2t+\frac 12 \times 0.8 t [ from equation (i)]

\Rightarrow 115=(4.2+0.4)t

\Rightarrow t= 115/4.6 = 25 seconds.

Hence, she takes 25 seconds to walk the distance.

5 0
3 years ago
A student walks 31 m east, then 16 m west. Make east positive. What is their<br> displacement?
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Displacement = 31 - 16 = +15 m
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3 years ago
If two objects A and B have the same kinetic energy but A has three times the momentum of B, what is the ratio of their inertias
Thepotemich [5.8K]

Answer:

\frac{inertia_B}{inertia_A}=9

Explanation:

First of all, let's remind that:

- The kinetic energy of an object is given by K=\frac{1}{2}mv^2, where m is the mass and v is the speed

- The momentum of an object is given by p=mv

- The inertia of an object is proportional to its mass, so we can write I=km, where k just indicates a constant of proportionality

In this problem, we have:

- K_A = K_B (the two objects have same kinetic energy)

- p_A = 3 p_B (A has three times the momentum of B)

Re-writing both equation we have:

\frac{1}{2}m_A v_A^2 = \frac{1}{2}m_B v_B^2\\m_A v_A = 3 m_B v_B

If we divide first equation by second one we get

v_A = 3 v_B

And if we substitute it into the first equation we get

m_A (3 v_B)^2 = m_B v_B^2\\9 m_A v_B^2 = m_B v_B^2\\m_B = 9 m_A

So, B has 9 times more mass than A, and so B has 9 times more inertia than A, and their ratio is:

\frac{I_B}{I_A}=\frac{km_B}{km_A}=\frac{9m_A}{m_A}=9

7 0
3 years ago
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