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mixer [17]
3 years ago
7

A student walks 31 m east, then 16 m west. Make east positive. What is their displacement?

Physics
1 answer:
Marianna [84]3 years ago
3 0
Displacement = 31 - 16 = +15 m
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Which of the following is proportional to the net external force acting on a body?
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A 750-kg automobile is moving at 16.8 m/s at a height of 5.00 m above the bottom of a hill when it runs out of gasoline. The car
anygoal [31]

Answer:h=19.4 m

Explanation:

Given

mass of automobile m=750\ kg

Initial height of automobile h_o=5\ m

Velocity at this instant v=16.8\ m/s

If the car stops somewhere at a height h

Thus conserving total energy we get

K_i+U_i=K_f+U_f

\frac{1}{2}mv^2+mgh_o=\frac{1}{2}m(0)^2+mgh

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h=19.4\ m

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Source localization in ocean acoustics is posed as a machine learning problem in which data-driven methods learn source ranges d
Temka [501]

Source localization in ocean acoustics is posed as a machine learning problem in which data-driven methods learn source ranges directly from observed acoustic data: True.

<h3>What is machine learning?</h3>

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3 years ago
A 4.00 m long, massless beam rests horizontally on a support 3.00 m from the left
Rus_ich [418]

If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m

Given the data in the question;

  • Length of the massless beam;L = 4.00m
  • Distance of support from the left end; x = 3.00m
  • First mass; m1 = 31.3 kg
  • Distance of beam from  the left end( m₁ is attached to ); x_1 = ?
  • Second mass; m_2 = 61.7 kg
  • Distance of beam from  the right of the support( m₂ is attached to ); x_1 = 0.273m

Now, since it is mentioned that the beam is in static equilibrium, the Net Torque on it about the support must be zero.

Hence, m_1g( x-x_1) = m_2gx_2

we divide both sides by g

m_1( x-x_1) = m_2x_2

Next, we make x_1, the subject of the formula

x_1 = x - [ \frac{m_2x_2}{m_1} ]

We substitute in our given values

x_1 = 3.00m - [ \frac{61.7kg\ * \ 0.273m}{31.3kg} ]

x_1 = 3.00m - 0.538m

x_1 = 2.46m

Therefore, If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m

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6 0
3 years ago
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