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mixer [17]
3 years ago
7

A student walks 31 m east, then 16 m west. Make east positive. What is their displacement?

Physics
1 answer:
Marianna [84]3 years ago
3 0
Displacement = 31 - 16 = +15 m
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you throw a rock with a horizontal velocity at 36.6 m/s out a window that is 29.5 m above the ground. What was it’s total time i
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29.5-4.9x^2= your answer
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What is the speed of a bobsled whose distance-time graph indicates that it traveled 116m in 29s?
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Speed = Distance ÷ Time
Speed = 116 ÷ 29
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The national high magnetic field laboratory holds the world record for creating the strongest magnetic field. for brief periods
max2010maxim [7]

Newton’s 2nd law states that Force is equal to the product of mass (m) and acceleration (a):

F = m a                                  ---> 1

While in magnetic forces, force can also be expressed as:

F = q v B                               ---> 2

where,

q = total charge

v = velocity = 45 cm / s = 0.45 m / s

B = the magnetic field = 85 T

First we solve for the total charge, q:

q = 3.8 × 10^-23 g (1 mol / 23 g) (6.022 × 10^23 electrons / mol) (1.602 × 10^-19 C / electron)

q = 1.594 × 10^-19 C

 

We equate equations 1 and 2 then solve for acceleration a:

m a = q v B

a = q v B / m

a = [1.594 × 10^-19 C * 0.45 m / s * 85 T] / 3.8 × 10-26 kg

a = 160,437,862.2 m/s^2

 

Therefore the maximum acceleration of Na ions is about 160 × 10^6 m/s^2.

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3 years ago
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A transformer has a primary coil with 106 turns and a secondary coil of 340 turns. The AC voltage across the primary coil has a
UkoKoshka [18]

To solve this problem it is necessary to apply the concepts related to transformers, that is to say passive electrical device that transfers electrical energy from one electrical circuit to one or more circuits.

From the mathematical definition we have that the relationship between the voltage of the first coil and the second coil is proportional to the number of loops of the first and second loop, that is:

\frac{V_s}{V_p} = \frac{N_s}{N_p}

Where

V_p =  input voltage on the primary coil.

V_s=input voltage on the secondary coil.

N_p=  number of turns of wire on the primary coil.

N_s = number of turns of wire on the secondary  coil.

Replacing our values we have:

V_p = 128V

N_p = 106

N_s = 340

Replacing,

\frac{V_s}{128} = \frac{340}{106}

V_s = 410.56V

From the same relations of number of turns and the voltage of the first and second coil we also have the relation of electricity and voltage whereby:

V_s I_s = V_p I_p

Where

I_p= Current Primary Coil

I_s = Current secundary Coil

Therefore:

I_s = \frac{V_p I_p}{V_s}

I_s = \frac{(128)(6)}{410.56}

I_s = 1.87 A

Therefore the maximum values for the secondary coil of the voltage is 410.56V and Current is 1.87A

5 0
3 years ago
A rock with a mass of 540 g in air is found to have an apparent mass of 342 g when submerged in water. (a) What mass of water is
AleksandrR [38]

(a) 198 g

When the rock is submerged into the water, there are two forces acting on the rock:

- its weight, equal to W=mg (m=mass, g=acceleration of gravity), downward

- the buoyant force, equal to B=m_w g (m_w=mass of water displaced), upward

So the resultant force, which is the apparent weight of the rock (W'), is

W'=W-B

which can be rewritten as

m'g = mg-m_w g

where m' is the apparent mass of the rock. Using:

m = 540 g

m' = 342 g

we find the mass of water displaced

m_w = m-m'=540 g-342 g=198 g

(b) 1.98\cdot 10^{-4} m^3

If the rock is completely submerged, the volume of the rock corresponds to the volume of water  displaced.

The volume of water displaced is given by

V_w = \frac{m_w}{\rho_w}

where

m_w = 198 g = 0.198 kg is the mass of the water displaced

\rho_w = 1000 kg/m^3 is the density of the water

Substituting,

V_w = \frac{0.198}{1000}=1.98\cdot 10^{-4} m^3

And so this is also the volume of the rock.

(c) 2727 kg/m^3

The average density of the rock is given by

\rho = \frac{m}{V}

where

m = 540 g = 0.540 kg is the mass of the rock

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Substituting into the equation, we find

\rho = \frac{0.540 kg}{1.98\cdot 10^{-4}}=2727 kg/m^3

3 0
3 years ago
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