Static friction is the friction that exists between two or more solids that are not moving with a relative speed. To calculate the static friction coefficient we use the formula Fs=us × n where Fs is the static friction , us is the coefficient of static friction and the n is the normal force.
thus the coefficient of static friction will be 5 N÷ 25 N = 0.2
Hence 0.2 is the coefficient of static friction
Answer:
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Answer:
0 N.
Explanation:
Force: This can be defined as the product of mass and the acceleration of the body. The S.I unit of force is Newton (N).
The expression of net force when both force act in the different direction is given as
F' = W-F ........................ Equation 1
Where F' = Net force on the bag, W = gravitational force on the bag, F = Force acting upward on the bag
Given: W = 18 N, F = 18 N.
Substitute into equation 1
F' = 18-18
F' = 0 N.
Hence the net force = 0 N.
Answer : 413.44N
Here it is given that an elevator is moving down with an acceleration of 3.36 m/s² . And we are interested in finding out the apparent weight of a 64.2 kg man . For the diagram refer to the attachment .
- From the elevator's frame ( non inertial frame of reference) , we would have to think of a pseudo force.
- The direction of this force is opposite to the direction of acceleration the frame and its magnitude is equal to the product of mass of the concerned body with the acceleration of the frame .
- When a elevator accelerates down , the weight recorded is less than the actual weight .
From the Free body diagram ,
- Mass of the man = 64.2 kg
