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Zinaida [17]
3 years ago
11

The average, year-after-year conditions of temperature, precipitation, winds, and cloud in an area are known as its

Physics
1 answer:
STatiana [176]3 years ago
6 0

Answer:

a. global warming

Explanation:

that's the definitain of global warming

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3. What is the gravitational force between a 70 kg physics student and her 1 kg textbook, at a distance of 1 meter? (This number
Rina8888 [55]

ANSWER

\begin{equation*} 4.67*10^{-9}\text{ }N \end{equation*}

EXPLANATION

Parameters given:

Mass of the student, M = 70 kg

Mass of the textbook, m = 1 kg

Distance, r = 1 m

To find the gravitational force acting between the student and the textbook, apply the formula for gravitational force:

F=\frac{GMm}{r^2}

where G = gravitational constant

Therefore, the gravitational force acting between the student and the textbook is:

\begin{gathered} F=\frac{6.67430*10^{-11}*70*1}{1^2} \\  \\ F=4.67*10^{-9}\text{ }N \end{gathered}

That is the answer.

6 0
1 year ago
Hello could yall answer my question <br>​
Rus_ich [418]
Density is a physical property derived from mass devided by volume (first part of the question)




m=v*p (p is rho)
m=9.5*60 =570 g
Density of water is 1g/cm^3 (centimeter cubed)
8 0
3 years ago
A change in the gravitational force acting on an object will affect the object
MArishka [77]
It is weight, if I understand your question.
4 0
3 years ago
A bucket of water of mass 10 kg is pulled at constant velocity up to a platform 30 meters above the ground. This takes 10 minute
Rudik [331]

Answer:

W = 2352 J

Explanation:

Given that:

  • mass of the bucket, M = 10 kg
  • velocity of pulling the bucket, v = 3m.min^{-1}
  • height of the platform, h = 30 m
  • time taken, t = 10 min
  • rate of loss of water-mass, m = 0.4 kg.min^{-1}

Here, according to the given situation the bucket moves at the rate,

v=3 m.min^{-1}

The mass varies with the time as,

M=(10-0.4t) kg

Consider the time interval between t and t + ∆t. During this time the bucket moves a distance

∆x =  3∆t meters

So, during this interval change in work done,

∆W = m.g∆x

<u>For work calculation:</u>

W=\int_{0}^{10} [(10-0.4t).g\times 3] dt

W= 3\times 9.8\times [10t-\frac{0.4t^{2}}{2}]^{10}_{0}

W= 2352 J

5 0
3 years ago
Your bike gets a flat tire. Its mass is 10 kg and you are able to accelerate your bike .5 m/s/s. What is the force on the bike..
STALIN [3.7K]

Answer:

50N

Explanation:

Given parameters:

Mass of the bike   = 10kg

Acceleration  = 5m/s²  

Unknown:

Force on the bike  = ?

Solution:

To solve this problem, we apply Newton's second law of motion.

  Force  = mass x acceleration

 Force  = 10 x 5 = 50N

6 0
3 years ago
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