Answer: check explanation
Explanation:
We know that V= √gr-----------------------------------------------------------------------------------------------------------------------(**)
Energy at the top of the loop;
= 1/2×m×V^2 + mg(2r)-------------------------------------------------------------------(1).
Potential energy= mgh-------------------------------------------------------------------(2).
Equating equation (1) and equation (2), we have;
=> 1/2×m×V^2 + mg(2r)= mgh-------------------------------------------------------(3).
=> 1/2(gr)+g(2r) = gh------------------------------------------------------------------(4).
Also, mg =mV^2/R-r---------------------------------------------------------------------(5).
Therefore, h in terms of the radius rloop of the loop is;
h=5/2× r_loop.