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4 years ago

How much force is needed to accelerate a 66kg skier at 2m/s^2

Physics

1 answer:

schepotkina [342]4 years ago

5 0

Answer:

= 66 kg x 2 m/s^2 = 132 N.

Explanation:

Thus, a force of 132 N is needed to accelerate a skier, having a mass of 66 kg, by 2 m/s^2. Note that we can also use the same equation to determine the weight of the skier.

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The acceleration of an object is inversely proportional to its mass, so if you decrease its mass while keeping the net force the

MaRussiya [10]

Answer:

True

Explanation:

Since acceleration is inversely proportional to mass, decreasing mass will make the object lighter, and thus easier to speed up. So acceleration increases as mass decreases and vice versa

5 0

2 years ago

Read 2 more answers

DONT ANSWER IF YOU DONT KNOW. For a person who is farsighted, what would they need to have a correct focal point?

fiasKO [112]

A) Convex Lens.... hope it helps :)

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3 years ago

One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching the f

Andreas93 [3]

Answer:

Part a)

$\theta_2 = 15 degree$

Part b)

$\Delta t = 2.88 s$

Explanation:

Part a)

In order to have same range for same initial speed we can say

$R_1 = R_2$

$\frac{v^2 sin2\theta_1}{g} = \frac{v^2 sin2\theta_2}{g}$

so after comparing above we will have

$\theta_1 = 90 - \theta$

so we have

$75 = 90 - \theta_2$

$\theta_2 = 15 degree$

Part b)

Time of flight for the first ball is given as

$T_1 = \frac{2vsin\theta}{g}$

$T_1 = \frac{2(20)sin75}{9.81}$

$T_1 = 3.94 s$

Now for other angle of projection time is given as

$T_2 = \frac{2(20)sin15}{9.81}$

$T_2 = 1.05 s$

So here the time lag between two is given as

$\Delta t = T_1 - T_2$

$\Delta t = 3.94 - 1.05$

$\Delta t = 2.88 s$

5 0

3 years ago

A force of 20 N acts on a smaller piston of a hydraulic press with an area of 10 dm2. How much force does the liquid act on a

ivann1987 [24]

Answer:

166.67 N

Explanation:

Applying Pascal's principle,

Presure in the smaller piston(P') = Pressure in the bigger piston(P)

But,

Pressure = Force/Area

Pressure in the smaller piston(P') = Force applied to the smaller piston(F')/Area of the smaller piston(A')

Pressure in the bigger piston(P) = Force applied to the bigger piston(F)/Area of the bigger piston(A)

F'/A' = F/A.................. Equation 1

Make F the subject of the equation

F = F'A/A'.............. Equation 2

From the question,

Given: F' = 20 N, A = 120 cm², A' = 10 dm² = (10×100) = 1000 cm²

Substitute these values into equation 2

F = 20(1000)/120

F = 166.67 N

3 0

3 years ago

An alien spaceship traveling at 0.600 c toward the Earth launches a landing craft. The landing craft travels in the same directi

Thepotemich [5.8K]

The distance to the Earth at the moment of the landing craft's launch as measured by the aliens is 0.16 light years.

To find the answer, we have to know about the Lorentz transformation.

<h3>What is the distance to the Earth at the moment of the landing craft's launch as measured by the aliens?</h3>

It is given that, an alien spaceship traveling at 0.600 c toward the Earth, in the same direction the landing craft travels with a speed of 0.800 c relative to the mother ship. We have to find the distance to the Earth at the moment of the landing craft's launch as measured by the aliens.

It is given that; the spaceship is 0.200 ly from the Earth when the landing craft is launched.
By Lorentz transformation equation, the value of the distance to the Earth at the moment of the landing craft's launch as measured by the aliens will be,

$L=L_0\sqrt{1-\frac{V^2}{c^2} } =0.2ly\sqrt{1-\frac{(0.6c)^2}{c^2} }=0.2ly\sqrt{1-0.36}= 0.16ly$

Thus, we can conclude that, the distance to the Earth at the moment of the landing craft's launch as measured by the aliens is 0.16 light years.

Learn more about the frame of reference here:

brainly.com/question/20897534

SPJ4

5 0

2 years ago