Answer:
h2 = 0.092m
Explanation:
From a balance of energy from point A to point B, we get speed before the collision:
Solving for Vb:
Since the collision is elastic, we now that velocity of bead 1 after the collision is given by:
Now, by doing another balance of energy from the instant after the collision, to the point where bead 1 stops, we get the distance it rises:
Solving for h2:
h2 = 0.092m
Responda:
1) E = 6 × 10 ^ 6NC ^ -1 2) Q = 6 × 10 ^ -5
Explicação:
Dado o seguinte:
Carga (q) = 3uC = 3 × 10 ^ -6C
Força elétrica (Fe) = 18N
Intensidade do campo elétrico (E) =?
1)
Lembre-se:
Força elétrica (Fe) = carga (q) * Intensidade do campo elétrico (E)
Fe = qE; E = Fe / q
E = 18N / (3 × 10 ^ -6C)
E = 6N / 10 ^ -6C
E = 6 × 10 ^ 6NC ^ -1
2)
Lembre-se:
E = kQ / r ^ 2
E = intensidade do campo elétrico
Q = carga de origem
r = distância de espera = 30cm = 30/100 = 0,3m
K = 9,0 × 10 ^ 9
6 × 10 ^ 6 = (9,0 × 10 ^ 9 * Q) / 0,3 ^ 2
9,0 × 10 ^ 9 * Q = 6 × 10 ^ 6 * 0,09
Q = 0,54 × 10 ^ 6 / 9,0 × 10 ^ 9
Q = 0,06 × 10 ^ (6-9)
Q = 0,06 × 10 ^ -3
Q = 6 × 10 ^ -5 = 60 × 10 ^ -6 = 60μC
Question:
A) C6H6
B) CH3CH2CH2CH2CH2COH6
C) NaCl
D) NH3
Answer:
The correct option is;
A) C₆H₆
Explanation:
Heat of fusion = 6.02 kJ/mol
Heat of vaporization =40.8 kJ/mol
Here, we analyze each of the options as follows
A) C₆H₆
Benzene has a melting point of 5.5° C and a boiling point of
80.1 ° C similar to water
Heat of fusion = 9.92 kJ/mol
Heat of vaporization =30.8kJ/mol
B) CH₃CH₂CH₂CH₂CH₂COH₆
The above compound is more likely solid
C) NaCl solid
D) NH₃ melting point = -77.73 °C boiling point = -33.34 °C
Of the above, the compounds the one that closely resembles water is C₆H₆
<span>reflection, rotation, translation</span>
