Answer:
B. The transition of heat across matter
Answer:
The answer to your question is given below.
Explanation:
Data obtained from the question include:
Sodium, Na => 1s2 2s2 2p6 3s1
Magnesium, Mg => 1s2 2s2 2p6 3s2
Aluminium, Al => 1s2 2s2 2p6 3s2 3p1
Sodium has 1 valence electron. If we remove the valence electron, sodium metal will become an ion. Thus, the electronic configuration becomes
1s2 2s2 2p6.
Magnesium has 2 valence electrons. If we remove the valence electrons, magnesium metal will be an ion. Thus, the electronic configuration becomes
1s2 2s2 2p6.
Aluminium has 3 valence electrons. If we remove the valence electrons, aluminum metal will become an ion. Thus, the electronic configuration becomes
1s2 2s2 2p6.
It's C, you're right.
Explanation:
A beta decay has the electron nuclei.
Answer:
See image attached and explanation
Explanation:
I have attached a detailed mechanism of the reaction to this answer. This reaction occurs by SN1 mechanism. It implies that the transition state involves a carbocation.
However, the initial carbocation formed is a primary carbacation. Remember that the order of stability of carbocations is methyl< primary < secondary< tertiary. This means that tertiary carbocations are the most stable carbocations. Tertiary carbocations are those in which the carbon atom bearing the carbon atom is attached to three other carbon atoms.
In the mechanism below, the substrate converts from a primary to a tertiary cabocation (most stable) by a 1,2-alkyl shift as shown giving the 3-ethoxy-3-methylpentane product.