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Reil [10]
3 years ago
6

Calculate the free-energy change for the dissolution of 1 mole of nabr and 1 mole of nai at 298 k, given that the values of δh°s

oln are –1 and –7 kj/mol for nabr and nai. the corresponding values of δs°soln are +57 and +74 j/(mol·k).
Chemistry
1 answer:
Georgia [21]3 years ago
7 0
The free energy, which has a symbol of ΔG° at standard conditions has the formula:

ΔG° = n(ΔH° - TΔS°)

For NaBr:
ΔG° = (1 mol)[(-1 kJ/mol)(1000 J/1 kJ) - (298 K)(57 J/mol·K)]
<em>ΔG° = -17,986 J</em>

For NaI:
ΔG° = (1 mol)[(-7 kJ/mol)(1000 J/1 kJ) - (298 K)(74 J/mol·K)]
<em>ΔG° = -29,052 J</em>
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What is the molar mass of <br> C4H9, 114.17 g/mol
mihalych1998 [28]

Answer:

4 x 12 +9 x 1= 56

Explanation:

I do not know what the 114.17 g/mol comes from

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3 years ago
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What is the formula of this<br> inorganic salt hydrate?
barxatty [35]

Salt hydrates are an important class of PCMs. An inorganic salt hydrate (hydrated salt or hydrate) is an ionic compound in which the ions attract a number of water molecules, which are then trapped inside the crystal lattice. A hydrated salt has the generic formula MxNy. nH2O.

7 0
2 years ago
A chemist encounters an unknown metal. They drop the metal into a graduated cylinder containing water, and find the volume chang
Mashutka [201]

Answer:

The density of the metal is 0.561 g/mL

Explanation:

The computation of the density of the metal is shown below;

As we know that

The Density of the metal is

= \frac{mass}{volume}

where,

Mass = 4.9g

Change in volume = 6.9 mL

Now place these values to the above formula

So, the density of the metal is

= \frac{4.9g}{6.9mL}

= 0.561 g/mL

Hence, the density of the metal is 0.561 g/mL

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5 0
3 years ago
Radar detectors use radio waves to measure the speed of moving
bagirrra123 [75]

Answer:

1.7x10^8 Hz

Explanation:

Frequency could be explained as the number of occurrences of a repeating event at a time

Given:

wavelength = 1.8 meters

The frequency f of the waves can be calculated using f = c / λ

Where c (m/s) is the speed of the wave

λ (m) is the wavelength

Speed c= 3*10^8 m/s

Frequency f= 3*10^8 /1.8

Frequency= 1.7x10^8 Hz

Therefore,the frequency of waves from a radar detector is 1.7x10^8 Hz

6 0
3 years ago
PLS HELP What is the mass of hydrogen atoms that is measured at 54 u?
tankabanditka [31]

The mass of hydrogen atoms that is measured at 54 u given the relationship is 89.64×10¯²⁴ g

<h3>Conversion scale </h3>

1 u = 1.66×10¯²⁴ g

<h3>How to determine the mass of hydrogen atoms </h3>
  • Mass of Hydrogen (u) = 54 u
  • Mass of Hydrogen (g) =?

1 u = 1.66×10¯²⁴ g

Therefore

54 u = 54 × 1.66×10¯²⁴ g

54 u = 89.64×10¯²⁴ g

Thus, the mass of the hydrogen atoms measured at 54 u is 89.64×10¯²⁴ g

Learn more about conversion:

brainly.com/question/2139943

#SPJ1

3 0
2 years ago
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