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almond37 [142]
3 years ago
13

A source emits a sound and is represented by the red dot in this map. Four people are located around the source, and the circles

represent the sound wave.
As the source moves west, which person hears the highest pitch?




-person A



-person B (not correct)



-person C



-person D
Physics
2 answers:
vladimir2022 [97]3 years ago
4 0

Answer:

A, person A

Explanation:

Just did it on edg!

klasskru [66]3 years ago
3 0

Answer:

person A

Explanation:

because the sound is moving twords them

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Thermopane window is constructed, using two layers of glass 4.0 mm thick, separated by an air space of 5.0 mm.
Bond [772]

To solve this problem it is necessary to apply the concepts related to rate of thermal conduction

\frac{Q}{t} = \frac{kA\Delta T}{d}

The letter Q represents the amount of heat transferred in a time t, k is the thermal conductivity constant for the material, A is the cross sectional area of the material transferring heat, \Delta T, T is the difference in temperature between one side of the material and the other, and d is the thickness of the material.

The change made between glass and air would be determined by:

(\frac{Q}{t})_{glass} = (\frac{Q}{t})_{air}

k_{glass}(\frac{A}{L})_{glass} \Delta T_{glass} = k_{air}(A/L)_{air} \Delta T_{air}

\Delta T_{air} = (\frac{k_{glass}}{k_{air}})(\frac{L_{air}}{L_{glass}}) \Delta T_{glass}

\Delta T_{air} = (\frac{0.84}{0.0234})(\frac{5}{4}) \Delta T_{glass}

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There are two layers of Glass and one layer of Air so the total temperature would be given as,

\Delta T = \Delta T_{glass} +\Delta T_{air} +\Delta T_{glass}

\Delta T = 2\Delta T_{glass} +\Delta T_{air}

20\°C = 46.9\Delta T_{glass}

\Delta T_{glass} = 0.426\°C

Finally the rate of heat flow through this windows is given as,

\Delta {Q}{t} = k_{glass}\frac{A}{L_{glass}}\Delta T_{glass}

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\Delta {Q}{t} = 179W

Therefore the correct answer is D. 180W.

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If a point has 40 J of energy and the electric potential is 8 V, the charge must be: A. 5 C

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Mathematically, the quantity of charge with respect to electric potential is given by the formula;

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Quantity \; of \; charge = \frac{40}{8}

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