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VARVARA [1.3K]
3 years ago
9

Can anybody help me with the wet lab on edgenuity? T-T

Chemistry
2 answers:
Jet001 [13]3 years ago
7 0
Is it the dry lab/wet lab week 1 or ?
Arte-miy333 [17]3 years ago
6 0

Answer:

I dont know if this is the right subject but i got an A+ on it. It is Life science edgenuity     This is the process part of it

Explanation:

First, I observed all of the arthropods that I would be using in my dichotomous key, Fire Ant, Bee, Butterfly, Dragonfly, Ladybug, Scorpion, Spider, and Wasp. I recorded my observations on a characteristics table that included Legs, Wings, Stinger, Antennae, and Claws.  

Next, I used my observations to create my first question, “Does the arthropod have a stinger?).  

     Then, I Looked over my notes and found the arthropds that have stingers, Fire Ant, Bee, Scorpion, and        Wasp, and sorted them into a Yes group. Also I found the arthropods in my notes that didn’t have stingers, Butterfly, Dragonfly, Ladybug, and Spider, and put them into a No group.  

     After That, I Chose a new question coming off of the Yes group, “Does the arthropod have 6 legs?”. I sorted those the arthropods that did have 6 legs into a Yes group, Fire Ant, Bee, and Wasp.  

     Then, I did the same for The arthropods who didn’t have 6 legs and the only one was Scorpion, so I wrote scorpion in the No group and that Branch was done.  

     Next, I did another question for my very first No group, “Does the arthropod have antennae?” and I sorted the arthropods into the yes and no branches. No group included, Dragonfly and Spider. Yes group included, Butterfly and Ladybug.

     Later, I did a question for the yes group coming off of the 6 legs question, “Does the arthropod have wings?”. The yes group included, Bee and Wasp. The no group included, the Fire Ant only so I wrote down Fire Ant and that branch was concluded.  

     Then, I did a question for the no group coming off of the antennae question, “Does the arthropod hve 8 legs?” and my yes group included spider only so that branch was done. My no group included Dragonfly so that branch was concluded aswell.  

     After That, I wrote a question for the yes group coming off of the wings question, “Does the arthropod have 2 wings?”. My Yes group concluded wit only the Wasp left so I had finished that branch. I finished my no group with a Bee.

     Lastly, I did my last question of the key coming off of the Yes group of the antennae question, “Does the arthropod have 4 wings?”. My no group included a Ladybug and my yes group included a Butterfly.

     In conclusion, My dichotomous key was finished with 8 athropods in each branch alone and now you can use the dichotomous to observe a Fire Ant, Bee, Wasp, Butterfly, Dragonfly, Ladybug, Spider, and Scorpion.  

                                               Please mark me brainliest :) :) :) :) :) :)

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Calculate the molarity of an hcl solution if a 10.00 ml sample requires 25.24 ml of a 1.600 m naoh solution to be neutralized.
AlladinOne [14]

Answer:

The molarity of the HCl solution should be 4.04 M

Explanation:

<u>Step 1:</u> Data given

volume of HCl solution = 10.00 mL = 0.01 L

volume of a 1.6 M NaOH solution = 25.24 mL = 0.02524 L

<u>Step 2:</u> The balanced equation

HCl + NaOH → NaCL + H2O

Step 3: Calculate molarity of HCl

n1*C1*V1 = n2*C2*V2

Since the mole ratio for HCl and NaOH is 1:1 we can just write:

C1*V1 =C2*V2

⇒ with C1 : the molarity of HCl = TO BE DETERMINED

⇒ with V1 = the volume og HCl = 10 mL = 0.01 L

⇒ with C2 = The molarity of NaOH = 1.6 M

⇒ with V2 = volume of NaOH = 25.24 mL = 0.02524 L

C1 * 0.01 = 1.6 * 0.02524

C1 = (1.6*0.02524)/0.01

C1 = 4.04M

The molarity of the HCl solution should be 4.04 M

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3 years ago
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moles CO₂ = 5.57.10⁻⁴

<h3>Further explanation   </h3>

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\tt mol=\dfrac{mass}{MW}

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Answer:

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Explanation:

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