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Leviafan [203]
3 years ago
15

What force is needed to accelerate a 1,000-kilogram car from a stop to 5 m/s/s?

Physics
1 answer:
solong [7]3 years ago
3 0
That depends on how soon you want it to reach 5 m/s/s. Without friction, ANY force will accelerate the car, like a mosquito pushing on it, but a Space Shuttle booster will accelerate it at a greater rate.
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if somebody swim to the right for 30 meters then swims to left for 15 meters and then swims back to the right for 50 meters what
zubka84 [21]

50m

Explanation:

Displacement is the length of path traveled which is measured from start to the finishing of the path.

    Analysis of the journey;

 Starts from:

 0                                    30m                                              from right

                  15m                                                                       to left

                                                                       50m              to right

                 

The displacement is 50m from the starting point.

Distance is total path traveled and for this problem it is 30+ 15 + 50 = 95m

learn more:

displacement brainly.com/question/5461768

#learnwithBrainly

8 0
3 years ago
Which statement is not a good practice when working inside a computer case?
lozanna [386]

Answer:

a. be sure to hold expansion cards by the edge connectors

Explanation:

Removal of loose jewelry is a good safety practice. Also not touching a microchip with a magnetized screwdriver is also a good practice.

But holding expansion cards by the edge connectors is not a good practice, so it is the odd one in the question. Therefore answer option a provides the correct and best answer to the question

3 0
3 years ago
PLS ANSWER FAST WILL GIVE BRAINLY!!!!!!
svet-max [94.6K]

Answer:

if somthing is warm or if somthing moves it usally has energy

6 0
3 years ago
If the load distance of a lever is 30 cm and the effort distance is 60 cm, calculate the amount of effort required to lift a loa
vladimir2022 [97]

Here,

Load distance (Ld) = 30 cm

Effort distance (Ed) = 60 cm

Load (L) = 200N

Effort (E) = ?

Now, By using formula,

or, E * Ed = L * Ld

or, E * 60 = 200 * 30

or, E = 6000/60

◆ E = 100N

This is a Right answer...

I hope you understand...

7 0
3 years ago
If a train is traveling at 85 mph I need to travel 17,000 feet how many hours will it take? Break it down to show the math
Ahat [919]
1 hour for the train to travel 17,000 feet
6 0
3 years ago
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