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vodka [1.7K]
2 years ago
5

(I NEED THIS ANSWERED QUICKLY! I WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWER!)

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
6 0

Answer:

B

Step-by-step explanation:

it's pretty simple dude

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For what values of q are the two vectors A = i + j + kq each other and B-iq-23 + 2kg perpendicular to
Sloan [31]

Answer:

The value of q are 0.781,-1.281.

Step-by-step explanation:

Given : Two vectors A=i+j+kq and B=iq-2j+2kq are perpendicular to each other.

To find : The value of q ?

Solution :

When two vectors are perpendicular to each other then their dot product is zero.

i.e. \vec{A}\cdot \vec{B}=0

Two vectors A=i+j+kq and B=iq-2j+2kq

(i+j+kq)\cdot (iq-2j+2kq)=0

(1)(q)+(1)(-2)+(q)(2q)=0

q-2+2q^2=0

2q^2+q-2=0

2q^2+q-2=0

Using quadratic formula,

q=\frac{-1\pm\sqrt{1^2-4(2)(-2)}}{2(2)}

q=\frac{-1\pm\sqrt{17}}{4}

q=\frac{-1+\sqrt{17}}{4},\frac{-1-\sqrt{17}}{4}

q=0.781,-1.281

Therefore, The value of q are 0.781,-1.281.

6 0
3 years ago
PLEASE HELP! 30 POINTS! What are the zeros of the function?
marusya05 [52]
Solve the equation
f(t) = 0
So we have:
{t}^{2}  - 13t + 36
Factor, 2 numbers of which the sum is -13 and multiplying gives 36, these two are -4 and -9
So solve:
(x - 4)(x - 9) = 0
The solutions:
4 and 9


4 0
3 years ago
A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of 2pi/3
Aloiza [94]
You can solve this problem and calculate the arc lenght, by applying the following formula:

 s=θr

 s: it is the arc lenght.
 θ: it is the central angle (θ=2π/3).
 r: it is the radius of the circle (r=10 inches).

 When you substitute these values into the formula, you obtain the arc lenght (s):

 s=θr
 s=(2π/3)(10)

 Then, you have that the value of the arc lenght is:

 s=20.94 inches
7 0
3 years ago
Read 2 more answers
Find the value of the expression. <br> pm + 4 <br> for m = 4 and p = 4
kvv77 [185]

m = 4, p = 4

Note that when two variables are placed directly next to each other, you are multiplying

plug in 4 for both m and p

(4)(4) + 4

Multiply

4 x 4 = 16

Add

16 + 4 = 20

20 is your answer

hope this helps

3 0
3 years ago
Find the probability that the person is frequently or occasionally involved in charity work.
Schach [20]
Given the table below which shows the result of a survey that asked 2,881 people whether they are involved in any type of charity work.

\begin{tabular}&#10;{|c|c|c|c|c|c|}&#10; &Frequently&Occassionally&Not at all&Total\\[1ex]&#10;Male&227&454&798&1,479\\&#10;Female &205&450&747&1,402\\&#10;Total&432&904&1,545&2,881&#10;\end{tabular}

Part A:

If a person is chosen at random, the probability that the person is frequently or occassinally involved in charity work is given by

P(being \ frequently \ involved \ or \ being \ occassionally \ involved)\\ \\= \frac{432}{2881} + \frac{904}{2881} = \frac{1336}{2881}=\bold{0.464}



Part B:

If a person is chosen at random, the probability that the person is female or not involved in charity work at all is given by

P(being&#10; \ female \ or \ not \ being \ involved)\\ \\= &#10;\frac{1402}{2881} + \frac{1545}{2881}-\frac{747}{2881} = &#10;\frac{2200}{2881}=\bold{0.764}



Part C:

If a person is chosen at random, the probability that the person is male or frequently involved in charity work is given by

P(being&#10; \ male \ or \ being \ frequently \ involved)\\ \\= &#10;\frac{1479}{2881} + \frac{432}{2881}-\frac{227}{2881} = &#10;\frac{1684}{2881}=\bold{0.585}



Part D:

If a person is chosen at random, the probability that the person is female or not frequently involved in charity work is given by

P(being&#10; \ female \ or \ not \ being \ frequently \ involved)\\ \\= &#10;\frac{1402}{2881} + \frac{904}{2881} + \frac{1545}{2881}-\frac{450}{2881}-\frac{747}{2881} = &#10;\frac{2654}{2881}=\bold{0.921}



Part E:

The events "being female" and "being frequently involved in charity work" are not mutually exclusive because being a female does not prevent a person from being frequently involved in charity work.

Indeed from the table, there are 205 females who are frequently involved in charity work.

Therefore, the answer to the question is "No, because 205 females are frequently involved charity work".
4 0
3 years ago
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