Answer:
(b) 16^(3/2)
Step-by-step explanation:
Your calculator is a good source of information about the values of numerical expressions.
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Here, all of the expressions have a value of 16 except 16^(3/2). That has the greatest value.
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<em>Additional comment</em>
Assuming you're familiar with powers of 2 and the rules of exponents, you can evaluate these without a calculator:
∛(64²) = ∛(2^6)² = (2^12)^(1/3) = 2^4
16^(3/2) = (2^4)^(3/2) = 2^6 . . . . . has the greatest value
√(16²) = ((2^4)^2)^(1/2) = 2^(4·2/2) = 2^4
∛(8^4) = ((2^3)^4)^(1/3) = 2^(3·4/3) = 2^4
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8= 2^3; 16 = 2^4; 64 = 2^6
(a^b)^c = a^(bc)
A root is equivalent to a fractional power. The cube root is the 1/3 power, for example.
2/7, 0/7, 1/3 or 1/4 since we are not sure who catches the bus
Answer:
min: 51.25
max: 68.75
Step-by-step explanation:
240-35=205
205/4=51.25
240+35=275
275/4=68.78
Answer:
y = -2(x -2)^2 + 11
Step-by-step explanation:
It works well to factor the leading coefficient from the first two terms.
... y = -2(x^2 -4x) +3
Now we want to add the square of half the x-coefficient inside parentheses, and subtract the equivalent quantity outside parentheses.
... y = -2(x^2 -4x +4) +3 - (-2·4)
... y = -2(x -2)^2 +11 . . . . . . . . simplify
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The form given in the problem statement is called "vertex form," where the vertex of the parabola is (h, k). A graph shows us the vertex is (2, 11), so we can write the function immediately as ...
... y = -2(x -2)^2 +11
Answer:
8-2
Step-by-step explanation:
Q(8, -2)
R(9,0)
S(8, 3)
T(7,0)