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viva [34]
3 years ago
5

What was the result of the Mexican army's victory over the Texan garrison at the Alamo?

Physics
2 answers:
sasho [114]3 years ago
3 0

The result of the Mexican victory was that fallen defenders became heroes to the cause of Texan independence.<span> The Battle of the Alamo took place between February 23 and March 6, 1836 and became the central episode of the Texas Revolution . After this thirteen-day battle, the Mexican troops of General President Antonio Lopez de Santa Anna began an attack on San Antonio de Bexar, the current San Antonio in Texas. The Battle of the Alamo fought the army of Mexico against a group of Texan rebels, mostly American settlers. More than four thousand men from Santa Ana stood in front of the Alamo Fort , the last stronghold of the rebels, which barely reached 187. The Alamo was not a fortress prepared to withstand a siege. It is believed that all the rebels of the Alamo died in the siege, but Santa Anna came to lose up to about 900 men during the days that lasted the fight. However, the worst result for Santa Ana was precisely the resistance that the Texan rebels had in the Alamo, which fostered the fighting spirit of the Texans. A few days later, on March 14, 1836, Texas became independent from Mexico and a month later, Santa Ana was imprisoned.</span>

KonstantinChe [14]3 years ago
3 0

The fallen defenders became heroes to the cause of Texan independence.

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8. do the earth and the moon always cast shadows? what do we call the occurrence where the earth passes within the shadow of the
Oduvanchick [21]

Yes, they both cast shadows. A  eclipse occurs when one enters the shadow of the other.

Solar eclipse: Earth in shadow of Moon.

Lunar eclipse: Moon in shadow of Earth.

A solar eclipse is the result of one celestial body being completely or partially obscured by another celestial body along the line of sight of an observer. A solar eclipse occurs when the moon passes between the earth and the sun, obscuring all or part of the sun's disk. A lunar eclipse occurs when the Moon passes through the Earth's shadow, making the Moon's surface completely or partially obscured.

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8 0
2 years ago
If the frequency of sound is doubled, how will its speed change? how will its wavelength change?
eimsori [14]

From the given equation we can deduce what changes will occur if the frequency of the sound is doubled

V= f (λ)

Speed = frequency. Wavelength  

When the frequency is doubled, speed will not change. Because speed depends on factors like temperature, air pressure, density of the gas. Since all these factors are unchanged thus speed will remain unchanged

Frequency is the number of waves produced per second. Frequency and wavelength are inversely proportional .Thus, if the frequency is doubled the wavelength would be halved.


6 0
4 years ago
Convert milligram to 1 gram
Bond [772]

Answer:

convert 1 milligram to 1 gram:

Explanation:

1 milligram is 0.001 gram.

so... 2 milligram is 0.002

3 milligrams is 0.003

and so on.

5 0
3 years ago
What happens to the potential energy of an object when it is falls from a height? A. Its is lost. B. It is converted into anothe
Damm [24]

Answer:

C. It is converted into another form, mainly kinetic energy

Explanation:

Potential energy is energy available to be used in an object that isn't currently moving. When an object begins moving, potential energy becomes kinetic energy.

7 0
3 years ago
Read 2 more answers
A 0.439 kg puck, initially at rest on a horizontal, frictionless surface, is struck by a 0.307 kg puck moving initially along th
lesya [120]

Answer:

u2 = 0.266 m/s

Explanation:

Let the left Puck mass at rest = m1 =0.307 Kg

mass of the right puck m2 = 0.439 kg

velocity of m1 before collision v1= 2.19 m/s

velocity of m2 before collision v2 = 0m/s

velocity of m1 after collision u1 =1.19 m/s

velocity of m2 after collision u2 = ? m/s

θ = 37°

<u>Solution:</u>

Before collision:

Momentum (y-axis ) before collision= 0 Kgm/s

Momentum (x-axis ) before collision= m1v1 + m2v2 = 0.307 Kg x 2.19 m/s + 0

= 0.672 Kgm/s

After collision:

Momentum (y-axis ) after collision= m1u1 sinθ  + m2u2 sinθ

= 0.307 x 1.19 m/s sin 37 °  + 0.439 x u2 sin 37°

= 0.22 + 0.26 u2

Momentum (x-axis ) after collision= m1u1 cosθ  + m2u2 cos θ

= 0.307 x 1.19 m/s cos 37 ° + 0.439 x u2 cos 37°

= 0.29 + 0.35 u2

According to law of conservation momentum

momentum before collision = momentum after collision.

0 + 0.672 Kgm/s =  0.22 Kgm/s  + 0.26 kg u2 + 0.29 Kgm/s + 0.35 kg u2

0.672 Kgm/s = 0.51 Kgm/s + 0.61 u2

u2 = 0.266 m/s

6 0
4 years ago
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