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viva [34]
3 years ago
5

What was the result of the Mexican army's victory over the Texan garrison at the Alamo?

Physics
2 answers:
sasho [114]3 years ago
3 0

The result of the Mexican victory was that fallen defenders became heroes to the cause of Texan independence.<span> The Battle of the Alamo took place between February 23 and March 6, 1836 and became the central episode of the Texas Revolution . After this thirteen-day battle, the Mexican troops of General President Antonio Lopez de Santa Anna began an attack on San Antonio de Bexar, the current San Antonio in Texas. The Battle of the Alamo fought the army of Mexico against a group of Texan rebels, mostly American settlers. More than four thousand men from Santa Ana stood in front of the Alamo Fort , the last stronghold of the rebels, which barely reached 187. The Alamo was not a fortress prepared to withstand a siege. It is believed that all the rebels of the Alamo died in the siege, but Santa Anna came to lose up to about 900 men during the days that lasted the fight. However, the worst result for Santa Ana was precisely the resistance that the Texan rebels had in the Alamo, which fostered the fighting spirit of the Texans. A few days later, on March 14, 1836, Texas became independent from Mexico and a month later, Santa Ana was imprisoned.</span>

KonstantinChe [14]3 years ago
3 0

The fallen defenders became heroes to the cause of Texan independence.

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Please help! I'd really appreciate it :-)
Alexxx [7]

Answer:

0.31429 Amps

Explanation:

Using the "Ohm's Law" we can look for the current (amps) with a formula of I = V/R

Given:

Resistance (Ohm) = 350

Volts = 110

Solution:

I = 110v/350r

I = 0.31429 amps

6 0
3 years ago
The position of a particle moving along an x axis is given by x = 14.0t2 - 2.00t3, where x is in meters and t is in seconds. det
Mumz [18]

a) x = 14t^{2} -2t^{3}

at t = 5s

x = 14*5^{2} -2*5^{3} = 14*25 - 2*125 = 350 - 250 = 100 m

b) v = \frac{dx}{dt}

       = 28t - 6t^2

at t = 5 s

v = 28*5-6*25 = 140 - 150 = -10 m/s

c) a = \frac{dv}{dt}

     = 28 - 12t

at t = 5 s

a = 28 -12*5= 28-60= -32 m/s^2

d) At maximum positive coordinate velocity = 0

So, 0 = 28t - 6t^2

         t = \frac{28}{6} = \frac{14}{3} = 4.66 s

  At t = 4.66 s

   X = 14 * 4.66^2 - 2* 4.66^3 = 202.39  m

e) At t = 4.66 s

f) At maximum positive velocity a = 0

   0=28-12t

   t = \frac{28}{12} = \frac{7}{3} = 2.33 s

At t = 2.33 s

V = 28*2.33- 6*2.33^2= 32.67 m/s

g) t = 2.33 s

h) When particle is not moving v = 0

So 0= 28t - 6 t^2

 t = \frac{28}{6} = 4.66 seconds

At t = 4.66 s

a = 28 - 12 * 4. 66 = -27.93m/s^2

i) At t = 0s, X =0m

       t = 5s, X = 100m

So, Displacement = 100m

Velocity = \frac{Displacement}{Time}  = \frac{100}{5} = 20m/s

8 0
3 years ago
(c) Nail tips exert tremendous pressures when they are hit by hammers because they exert a large force over a small area. What f
ziro4ka [17]

Answer:

Force, F = 2356.19 N

Explanation:

Given that,

Diameter of the circular tip, d = 1 mm = 0.001 m

Its radius, r = 0.0005 m

Pressure created, P=3\times 10^9\ N/m^2

To find,

Force exerted on the nail.

Solution,

The pressure exerted by an object is equal to the force acting per unit area. Its formula is given by :

P=\dfrac{F}{A}

F=P\times A

F=3\times 10^9\ N/m^2\times \pi (0.0005\ m)^2

F = 2356.19 N

Therefore, the force exerted on the nail is 2356.19 N.

6 0
3 years ago
I REALLY NEED HELP PLEASE
iogann1982 [59]
The correct answer is C
6 0
4 years ago
Why does gravity hold objects on earth?
LUCKY_DIMON [66]
 
Gravity is an attractive force that works to pull objects together. If 2 objects are close the gravitational pull will be stronger 
Mass and distance determine gravity. The farther two things are away from each other, the weaker the gravitational forces are, the less mass an object has the less gravitational force it exerts
6 0
4 years ago
Read 2 more answers
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