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Virty [35]
3 years ago
9

Equation need answers not quite sure

Physics
1 answer:
scoray [572]3 years ago
8 0
6 molecules of carbon dioxide
1 molecule of sugar produced
6 carbon atoms on the left
6 carbon atoms on the right
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Joey throws a football 30 meters with a force of 10 N. How much work<br> does Joey do?
stich3 [128]

Answer:

300 Joules

Explanation:

Just use the Work formula:

W = F . D

W = 10 . 30

W = 300 Joules

8 0
3 years ago
Water freezes at _____. 273°c -273°c 273 k -273 k
AURORKA [14]
273 k hope this helps :)
6 0
3 years ago
Read 2 more answers
A 1500 kg truck traveling at 80 km/h collides with another car of mass 1000 kg traveling at 30 km/h in the same direction. The t
Likurg_2 [28]

Answer:

Their speed immediately after the collision is 60 km/h

Explanation:

The magnitude that characterizes the state of motion of a body is called the quantity of motion. The momentum of a particle of mass m moving with velocity v is defined as the product of mass and velocity:

p=m*v

Newton's second law states that to accelerate an object you must apply a force to it. In other words, to change the moment of an object, an impulse must be applied to it, an impulse that is produced by a force. In both cases there is an external agent that exerts the force or the impulse, the internal forces are not considered. When the force  net is zero, so the net momentum is zero, and therefore there is no change in total momentum. Then it can be stated that if a net force is not exerted on a system, the total moment of the system cannot change.

In summary, the principle of conservation of linear momentum, also known as the principle of conservation of momentum, states that if the resultant of the forces acting on a body or system is zero, its momentum remains constant in time.

Then before collision, the momentum of truck is  1,500 kg*80 km/h = 120,000 kg.km/h  and the momentum of car is  1,000 kg* 30 km/h = 30,000 kg.km/h

So, the total momentum before collision is  120,000 kg*km/h+ 30,000 kg*km/h = 150,000 kg.km/h

The two cars stick together after the collision. This means that the speed V of both is the same. Therefore, the momentum after collision is  

V*(1,500 kg + 1,000 kg)  = V*2,500 kg

Applying the law of conservation of momentum, that it states that the total momentum of two objects before collision is equal to the total momentum of the two objects after collision., you get:

150,000 kg.km/h= V*2,500 kg

Solving:

V=\frac{ 150,000 kg.km/h}{2,500 kg}

V= 60 km/h

<u><em>Their speed immediately after the collision is 60 km/h</em></u>

7 0
3 years ago
If the car’s speed decreases at a constant rate from 71 mi/h to 50 mi/h in 3.0 s, what is the magnitude of its acceleration, ass
melisa1 [442]

Answer:

The acceleration and the distance are 25200 mi/h² and 0.1008 mi.

Explanation:

Given that,

Initial speed = 71 mi/h

Final speed = 50 mi/h

Time = 3.0 s

(a). We need to calculate the acceleration

Using equation of motion

v=u+at

a=\dfrac{v-u}{t}

Put the value in the equation

a=\dfrac{(50-71)\times3600}{3}

a=-25200\ mi/h^2

Negative sign shows the deceleration.

(b). We need to calculate the distance

Using equation of motion

v^2=u^2+2as

(50)^2=(71)^2+2\times(-25200)\times s

s=\dfrac{(50)^2-(71)^2}{-25200}

s=0.1008\ mi

Hence, The acceleration and the distance are 25200 mi/h² and 0.1008 mi.

8 0
3 years ago
A clarinetist, setting out for a performance, grabs his 3.230 kg3.230 kg clarinet case (including the clarinet) from the top of
SpyIntel [72]

Answer:

- 0.5 m/s²

Explanation:

m = mass of the clarinet case = 3.230 kg

W = weight of the clarinet case in downward direction

a = vertical acceleration of the case

Weight of the clarinet case is given as

W = mg

W = 3.230 x 9.8

W = 31.654 N

F = Upward force applied = 30.10 N

Force equation for the motion of the case is given as

F - W = ma

30.10 - 31.654 = 3.230 a

a = - 0.5 m/s²

8 0
3 years ago
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