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3 years ago

Equation need answers not quite sure

Physics

1 answer:

scoray [572]3 years ago

8 0

6 molecules of carbon dioxide
1 molecule of sugar produced
6 carbon atoms on the left
6 carbon atoms on the right

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Two vehicles approach a right angle intersection and then suddenly collide. After the collision, they become entangled. If their

geniusboy [140]

Answer:

a. 11 m/s at 76° with respect to the original direction of the lighter car.

Explanation:

In this exercise, since both cars make a right angle, let's assume that the lighter car only has a horizontal velocity component (vx) and that the heavier one only has a vertical velocity component (vy). The final velocities for both components for the system can be determined as:

$m_{1} v_{x1}+m_{2}v_{x2}=(m_{1}+m_{2})v_{fx}\\m_{1} v_{y1}+m_{2}v_{y2} =(m_{1}+m_{2})v_{fy}$

Assume that the lighter car has a 1kg mass and that the heavier car has a 4 kg mass.

$1*13 + 4*0 = (1+4) v_{fx}\\v_{fx}=\frac{13}{5} =2.6\\1*0 + 4*13 = (1+4) v_{fy}\\v_{fy}=\frac{13*4}{5} =10.4\\$

The magnitude of the final velocity of the wreck can be found as:

$v_{f}^{2}= v_{fx}^{2}+ v_{fy}^{2}\\v_{f}=\sqrt[]{2.6^{2} + 10.4^{2}} \\v_{f}= 10.72$

The final velocity has an intensity of roughly 11 m/s

As for the angle, it can be determined in respect to the lighter car (x axis) as follows:

$\theta = cos^{-1}(\frac{v_{fx} }{v_{f}} )\\\theta = cos^{-1}(\frac{2.6}{10.7} )\\\theta = 76^{o}$

Therefore, the wreck has a velocity with an intensity of 11 m/s at 76° with respect to the original direction of the lighter car.

5 0

3 years ago

6. What disadvantages or pitfalls might be associated with using a fa ce book classroom page? Name at least two and discuss why

Novosadov [1.4K]

Answer:

poultion and canser

Explanation:

4 0

3 years ago

A spherical hot air balloon of diameter 30.0 meters just floats (hovers) when the hot air inside has been heated to a density of

Rom4ik [11]

Answer:

W = 166422.729 N

Explanation:

given,

diameter of the balloon = 30 m

density of the air = 1.10 Kg/m³

weight of the balloon and cargo = ?

density of the surrounding air = 1.20 kg/m³

we know,

Density = mass/volume

m = density x volume

$m = \rho\times \dfrac{4}{3}\pi r^3$

$m =1.20 \times \dfrac{4}{3}\pi\times 15^3$

m = 16964.6 Kg

Weight of the balloon

W = m g

W = 16964.6 x 9.81

W = 166422.729 N

Weight of the balloon and the cargo is equal to W = 166422.729 N

5 0

3 years ago

Three short square wood blocks measuring 3.5 per side support a machine weighing 29500 lbs. What is the compressive stress in th

Ilya [14]

Answer:

D. 803 lbs

Explanation:

In order to find the compressive stress on all three blocks we first need to find the normal surface area of each:

Surface Area of 1 Block = 3.5 x 3.5

Surface Area of 1 Block = 12.25

Surface Area of all 3 Blocks = A = 3 x 12.25

Area = 36.75

Now, the stress is given by the following formula:

Stress = Force/Area

Stress = 29500 lbs/36.75

Stress = 802.72 lbs

Hence, the correct option will be:

4 0

3 years ago

4) T F If two objects have the same moment of inertia, they must have the same mass.

lisov135 [29]

Answer:

False

Explanation:

The moment of inertia for a rigid body is given by

$I=\int \rho(r) r^2 dV$

where

$\rho(V)$ is the density distribution of the object

r is the distance from the axis of rotation of the object

Essentially, the moment of inertia does not depend only on the mass of the object, but also on its shape. For example: for a solid cylinder, the moment of inertia derived from the formula above is

$I=\frac{1}{2}MR^2$

where M is the mass of the cylinder and R is its radius. As we see, I (moment of inertia) does not depend on the mass only: therefore, if two objects have same moment of inertia, this does not imply that they also have the same mass.

4 0

3 years ago