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Lynna [10]
3 years ago
14

if the accuracy in measuring the position of a particle increases, what happens to the accuracy in measuring its velocity?

Physics
1 answer:
erastova [34]3 years ago
7 0
The answer to this question should be: The accuracy in measuring its velocity decreases

Hope I helped
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Answer:

The answer to your question is given below.

Explanation:

Mechanical advantage (MA) = Load (L)/Effort (E)

MA = L/E

Velocity ratio (VR) = Distance moved by load (l) / Distance moved by effort (e)

VR = l/e

Efficiency = work done by machine (Wd) /work put into the machine (Wp) x 100

Efficiency = Wd/Wp x100

Recall:

Work = Force x distance

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Work done by machine (wd) = load (L) x distance (l)

Wd = L x l

Work put into the machine (Wp) = effort (E) x distance (e)

Wp = E x e

Note: the load and effort are measured in Newton (N), while the distance is measured in metre (m)

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Efficiency = (L x l) / (E x e) x 100

Rearrange

Efficiency = L/E ÷ l/e x 100

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MA = L/E

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Efficiency = L/E ÷ l/e x 100

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