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astra-53 [7]
3 years ago
15

A car company is testing seatbelts using crash test dummies. The company finds that when cars come to a sudden stop, the crash t

est dummies' bodies continue to move forward. The seat belt keeps the crash test dummies from hitting the back of the seat in front of them. Why do the crash test dummies' bodies continue to move forward even though the car stopped?
Physics
2 answers:
amid [387]3 years ago
7 0

Answer:

B

Explanation:

professor190 [17]3 years ago
6 0

Answer: Because of Inertia

Explanation: According to Newton first law, that a body in a linear motion will continue to be in motion except an external for act on it

But also, a body in motion will always like to continue in motion and have a reluctance tendency to stop because of inertia.

the crash test dummies' bodies will continue to move forward even though the car stopped because of inertia.

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Explanation:

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2 years ago
How would you describe the difference between momentum and angular momentum?
zheka24 [161]

Answer:

Analogous

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3 0
3 years ago
Two boys want to balance a seesaw perfectly. One boy weighs 120 pounds and is sitting four feet from the fulcrum. The other boy
OLEGan [10]

Basically a distance multiplied by a weight that is equal to the distance that is going to be multiplied by the weight. (for the equation we will use X for the distance).

equation: 4 x1 20 = ? x 80

Now step one: 4(120) = X(80)  

Or another way is 480 = 80X  

480/80 = X  

48/8= X  

X = 6

I hope this could help! Sorry if it didn't make much sense otherwise!


6 0
3 years ago
Is a vector necessarily changed if it is rotated through an angle ?​Explain
gavmur [86]
Yes, since it depends on the normal and resultant
6 0
4 years ago
Suppose the mass of a fully loaded module in which astronauts take off from the Moon is 12,900 kg. The thrust of its engines is
Alexandra [31]

Answer:

Acceleration a=0.5 m/s²

Explanation:

Given data

Mass m=12,900 kg=1.29×10⁴kg

Thrust of engine F=28,000 N=2.8×10⁴N

gravitational acceleration g=1.67 m/s²

To find

Acceleration

Solution

As we know  that

W_{weigth}=mg\\ W=(1.29*10^{4}kg )(1.67m/s^{2} )\\W=21543N

The net force can be given as

F_{net}=F_{thrust}-W\\F_{net}=(2.8*10^{4}-21543)N\\   F_{net}=6457 N

From Newtons second law of motion we know that

F=ma\\a=F/m\\a=\frac{6457N}{12,900kg}\\ a=0.5m/s^{2}

6 0
3 years ago
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