1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lianna [129]
3 years ago
11

What is the required force to bring a 1550 kg vehicle moving at 32 m/s to a stop in a distance of 45 m?

Physics
1 answer:
Vilka [71]3 years ago
8 0
The answer is 9 i think.
You might be interested in
Why is energy transferred from the substance to the surroundings when a substance freezes
jeyben [28]
Zalice sucks chakra woman trAnsfer to the fezze y try e
7 0
3 years ago
A girl rides her scooter to school, a total distance of 4.5km. She has to slow down twice to cross busy streets, but overall the
Whitepunk [10]

Answer:

6.93 km/h

Explanation:

To calculate her average speed, we need the "speed" formula, which is:

average speed = distance / time

You plug in your numbers and it will give you the answer.

Speed = 4.5km/0.65hr

           = 6.923 km/h

8 0
3 years ago
Read 2 more answers
How does the diameter of the disk of milky way galaxy compare to its thickness?
weqwewe [10]
The diameter is about 100 times as great as the thickness.
7 0
3 years ago
An object of mass m is hung from a spring and set into oscillation. The period of the oscillation is measured and recorded as T.
sergejj [24]

Answer:\sqrt{2}T

Explanation:

Given

object of mass m is suspended from spring and set in oscillation with time Period T

We know Time period of a mass in oscillation is given by

T=2\pi \sqrt{\frac{m}{k}}

where k=spring constant

When mass m is replaced by a mass of 2 m time period is given by

T'=2\pi \sqrt{\frac{2m}{k}}

T'=\sqrt{2}\times 2\pi \sqrt{\frac{m}{k}}

T'=\sqrt{2}T

i.e. New time period becomes \sqrt{2} times of previous one

                         

7 0
3 years ago
How do you find the force of a ping-pong ball rolling down a track?
Kaylis [27]

Answer:

Weight

a) weight's vertical component = Normal upward force

b) weight's horizontal component = Friction force = (mass of ball)(acceleration)

These forces depend upon the track,

1) inclined or horizontal

2) steepness.

Explanation

The force of gravity points straight down, but a ball rolling down a ramp doesn't go straight down, it follows the ramp. Therefore, only the component of the weight which points along the direction of the ball's motion can accelerate the ball.

weight's horizontal component = Friction force = (mass of ball)(acceleration)

The other component pushes the ball into the ramp, and the ramp pushes back.

If the ramp is horizontal, then the ball does not accelerate, as gravity pushes the ball into the ramp and not along the surface of the ramp. Hope this helps. Can u give me brainliest

Explanation:

3 0
3 years ago
Other questions:
  • Hi to answer this question you need to be in 5th grade or older
    10·1 answer
  • Help help help please , i will give brainliest
    5·2 answers
  • What force is necessary to accelerate a 70-kg object at a rate ifm4.2 m/s
    9·1 answer
  • What are examples of astronomical cycles
    10·1 answer
  • Why do the compass needles change direction when the electric current is Flowing
    10·2 answers
  • C
    9·1 answer
  • Help me with this homework
    10·1 answer
  • A periodic wave has a wavelength of 0,50 m and a speed of 20 m/s, What is the wave frequency?
    13·1 answer
  • Two concentric, coplanar, circular loops of wire of different diameter carry currents in the same direction. Describe the nature
    8·1 answer
  • the force that gravitation exerts upon a body, equal to the mass of the body times the local acceleration of gravity
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!