Answer:
d = 44.64 m
Explanation:
Given that,
Net force acting on the car, F = -8750 N
The mass of the car, m = 1250 kg
Initial speed of the car, u = 25 m/s
Final speed, v = 0 (it stops)
The formula for the net force is :
F = ma
a is acceleration of the car
Let d be the breaking distance. It can be calculated using third equation of motion as :
So, the required distance covered by the car is 44.64 m.
Answer:
What will be the increase in frequency if these waves are reflected = 2979.63Hz
Explanation:
The detailed steps and appropriate formula is as shown in the attached file.
<h2>Question:- </h2>
Which of the diagrams shows the least gravitational force between the two objects?
<h2>Options :- </h2>
a. I
b. II
c. III
d. IV
<h2>Answer :- Option D . IV </h2>
<h2>Explanation :- </h2>
- Gravitational force directly proportional to both the masses and in 4th and 3th case we have least mass of 2 on both side which is less than 10 in 2 cases
- Gravitational force is inversely proportional to square of the distance between the masses and in case 1st and 4th we have more distance than in 2nd and 3th . we know larger the distance lesser will be the force
From above observation we can conclude that gravitational force is least in 4th case because we have less mass on both side and we have more distance between the 2 masses that others with same mass .
