Answer:
(A) Angular speed 40 rad/sec
Rotation = 50 rad
(b) 37812.5 J
Explanation:
We have given moment of inertia of the wheel 
Initial angular velocity of the wheel 
Angular acceleration 
(a) We know that 
We have given t = 2 sec
So 
Now 
(b) After 3 sec 
We know that kinetic energy is given by 
The formula for work is
F*d
Therefore work=2.0N*3.0=6N*m
B because the the organism is changing into another chemical form
Answer:
B) Power is the rate at which work is done