Answer:
330.5 m
Explanation:
In this case, the object is launched horizontally at 30° with an initial velocity of 40 m/s .
The maximum height will be calculated as;

where ∝ is the angle of launch = 30°
vi= initial launch velocity = 40 m/s
g= 10 m/s²
h= 40²*sin²40° / 2*10
h={1600*0.4132 }/ 20
h= 661.1/2 = 330.5 m
Answer:
so his far point according to this pair of glass is 200 cm
Explanation:
power of old pair of corrective glasses is given as

now we have



now we know that for normal vision the maximum distance of vision is for infinite distance
so by lens formula we have



so his far point according to this pair of glass is 200 cm
Answer:
If the body is in equilibrium the two forces add up and the third is the opposite of the resultant.
F(1x)=F(1)=10 N
F(2x)=F(2)cos60=5•0.5=2.5 N
F(2y) =F(2)sin60 = 5•0.866= 4.33 N
F(3x) =- F(x)=- (10+2.5 )= -12.5 N
F(3y) =- F(2y)= - 4.33 N
F(3) = sqrt{ F(3x)²+F(3y)²} =13.23 N
tan φ = F(3y)/F(3x) =4.33/12.5=0.364
φ = 19.1⁰ (south-west)
Explanation:
Answer:
Rebounding involves a change in the direction of an object; the before- and after-collision direction is different. ... As mentioned above, if cars rebound upon collision, the momentum change will be larger and so will the impulse. A greater impulse will typically be associated with a bigger force.
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Answer:
A
Explanation:
i dont really have an explanation but it just seems correct yk?