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sukhopar [10]
3 years ago
6

The surface of the sun has a temperature of about 5,800 Kelvin. What is the average kinetic energy of particles on the surface o

f the sun? Please show your work

Physics
1 answer:
LenaWriter [7]3 years ago
5 0

Answer:

273.15

Explanation:

So that's three over two times 1.38 times ten to the minus twenty-three joules per Kelvin, times 5500 degrees Celsius, the surface of the sun converted into Kelvin by adding 273.15. This works out to 1.20 times ten to the minus nineteen joules. So that's the average kinetic energy of hydrogen atoms.

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7. Which law describes when a person lands on a
marissa [1.9K]

Answer:

Newton's Third Law

Explanation:

Newton's third law

Newton's third law: “for every action, there is an equal and opposite reaction.” This is where you get the bounce. When you push down on the trampoline (or fall downward onto the trampoline bed), Newton's third law says that an equal and opposite reaction pushes back.

:)

6 0
3 years ago
Read 2 more answers
An acorn with a mass of .0300 kg is hanging from a branch in a tree it is 2.50 M off the ground what is the potential energy of
Alekssandra [29.7K]
According to another source this is what I got
<span>0.735 J ( Ep-potential energy, m-mass,g-gravitational acceleration = 9.81m/s², h-height; Ep = m * g * h; Ep = 0.0300 kg * 9.81 m/s² * 2.5 m ) 
</span>Hope it helps
5 0
3 years ago
Read 2 more answers
Two masses are attracted by a gravitational force of 7 N.
damaskus [11]

Answer:

The answer to your question is: F  = 0.4375 N. The force will be 16 times lower than with the first conditions.

Explanation:

Data

F = 7 N

F = ?  if the masses is quartered

Formula

F = \frac{Km1m2}{r2}

Process

Normal conditions F = Km₁m₂/r²  = 7              

When masses quartered        F = K(m₁/4)(m₂/4)/r²  = ?

                                                F = K(m₁m₂/16)/r²

                                                F = K(m₁m₂/16r²      = 7/16  = 0.4375 N

3 0
3 years ago
What is the kinetic energy of a car of 1500 kg moving 25 m/s?
Ivan
Is this a multi choice?
4 0
3 years ago
A fan that is rotating at 960 rev/s is turned off. It makes 1500 revolutions before it comes to a stop. a) What was its angular
Evgesh-ka [11]

Answer:

α = 1930.2 rad/s²

Explanation:

The angular acceleration can be found by using the third equation of motion:

2\alpha \theta=\omega_f^2-\omega_i^2

where,

α = angular acceleration = ?

θ = angular displacement = (1500 rev)(2π rad/1 rev) = 9424.78 rad

ωf = final angular speed = 0 rad/s

ωi = initial angular speed = (960 rev/s)(2π rad/1 rev) = 6031.87 rad/s

Therefore,

2\alpha(9424.78\ rad) = (0\ rad/s)^2-(6031.87\ rad/s)^2\\\\\alpha = -\frac{(6031.87\ rad/s)^2}{(2)(9424.78\ rad)}

<u>α = - 1930.2 rad/s²</u>

<u>negative sign shows deceleration</u>

5 0
3 years ago
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